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LinkedIn REST API 的许多代码示例和工具都假设您已使用 Oauth1 进行识别,因此您已获得会员令牌和会员密码。

现在,LinkedIn 在此处提供的示例代码:http: //developer.linkedin.com/documents/code-samples 可以获取 Oauth2 access_token。

获得 access_token 后,您可以使用代码示例中提供的 fetch 函数进行查询并获取成员的详细信息

function fetch($method, $resource, $body = '') {


 $params = array('oauth2_access_token' => $_SESSION['access_token'],
                    'format' => 'json',
              );

    // Need to use HTTPS
    $url = 'https://api.linkedin.com' . $resource . '?' . http_build_query($params);
    // Tell streams to make a (GET, POST, PUT, or DELETE) request
    $context = stream_context_create(
                    array('http' =>
                        array('method' => $method,
                        )
                    )
                );


    // Hocus Pocus
    $response = file_get_contents($url, false, $context);

    // Native PHP object, please
    return json_decode($response);
}

好的,太好了,这非常有效。但是提供的 fetch 函数假定 body 为 NULL。但是要使用/v1/people/~/person-activities发布网络更新,您需要在正文中传递一些 XML。我尝试了很多方法,找到了几十个使用 Oauth 1.0 成员令牌和成员密码的示例。但是当您只有一个 Oauth2 access_token 时,我还没有找到任何可行的解决方案。所以问题是:这个 fetch 函数需要进行哪些更改才能在查询中传递 XML 正文?

4

1 回答 1

3

最后,我找到了答案。

function GetXMLTemplate(){
   string = '<?xml version="1.0" encoding="UTF-8"?><activity locale="en_US">
   <content-type>linkedin-html</content-type>
   <body>xml_content</body>
   </activity>';
   return $string;
 }

 public function PostActivity($message) {   
    $details = $this->GetLinkedInDetails(); //own function returning basic details in Stdobject
    $url = 'https://api.linkedin.com/v1/people/~/
       person-activities?oauth2_access_token='.$this->access_token;
    // build your message
    $txt = '<a href="'.$details->siteStandardProfileRequest->url.'">'.$details->firstName.
           ' '.$details->lastName.'</a> '.$message;
    //the below str_replace is only required because the activity contains a <a> tag
    //if you don't have one, just keep the htmlspecialchars
    $txt = str_replace("&","&amp;",htmlspecialchars($txt,ENT_QUOTES,'UTF-8'));
    $ch = curl_init($url);
    curl_setopt($ch, CURLOPT_POST, true);
    curl_setopt($ch, CURLOPT_POSTFIELDS,str_replace('xml_content',$txt,$this->GetXMLTemplate()));
    curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
    curl_setopt($ch, CURLOPT_HTTPHEADER, array('Content-type: application/xml'));
    $response = curl_exec($ch);
    $http_status = curl_getinfo($ch, CURLINFO_HTTP_CODE);
    curl_close($ch);
    print_r($response);
    echo $http_status;
}
于 2013-04-07T09:47:54.637 回答