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我正在使用 HttpUnit 来模拟这个网站：http ://www.voyages-sncf.com/ 这是我的代码：它不会向我发送最终的重定向 url，只是用于搜索的 url，而不是结果

public class TestHttpUnit {

    public static void main(String[] args) throws Exception {

        // Create and initialize WebClient object
        WebClient webClient = new WebClient(BrowserVersion.FIREFOX_10);
        webClient.setThrowExceptionOnScriptError(false);
        webClient.setRefreshHandler(new RefreshHandler() {
            public void handleRefresh(Page page, URL url, int arg) throws IOException {
                    System.out.println("handleRefresh");
            }
        });

        // visit Yahoo Mail login page and get the Form object
        HtmlPage page = (HtmlPage) webClient.getPage("http://www.voyages-sncf.com/");
        //Trouver le formulaire par le nom
        HtmlForm form = page.getFormByName("TrainTypeForm");
        //Trouver le formulaire avec l'action 
        //HtmlForm form = page.getFirstByXPath("//form[@action='http://www.voyages-sncf.com/dynamic/expressbooking/_SvExpressBooking']");


        // Enter login and password of 
        form.getInputByName("origin_city").setValueAttribute("paris");
        form.getInputByName("destination_city").setValueAttribute("marseille");
        form.getInputByName("outward_date").setValueAttribute("29/03/2013");


        // Click "Sign In" button/link
        page = (HtmlPage) form.getInputByValue("Rechercher").click();



        System.out.println(page.asText());
    }
}
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1 回答 1

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根据HTTP Unit cookbook，表单提交应该这样处理：

WebForm form = resp.getForms()[0];      // select the first form in the page
// ... fill in form fields, and finally:
form.submit();                          // submit the form

之后，您将进入“等待”屏幕。我还没有尝试过，但也许你应该做这样的事情（伪代码）：

do {
    // Wait a while
    wc.waitForBackgroundJavaScript(3000);
    // Somehow refresh the page, since that's what your browser might do, too
} while (someTestToVerifyThatYoureStillOnTheWaitingPage(wc));
于 2013-03-28T10:56:48.537 回答