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我为调用 Web 服务创建了一个简单的类

public class CallSoap {
    public final String SOAP_ACTION = "http://tempuri.org/Add";

    public  final String OPERATION_NAME = "Add"; 

    public  final String WSDL_TARGET_NAMESPACE = "http://tempuri.org/";

    public  final String SOAP_ADDRESS = "http://localhost:41614/Service1.asmx";
    public CallSoap() 
    { 
    }
    public String Call(int a,int b)
    {
    SoapObject request = new SoapObject(WSDL_TARGET_NAMESPACE,OPERATION_NAME);
    request.addProperty("a",a);
    request.addProperty("b",b);

    SoapSerializationEnvelope envelope = new SoapSerializationEnvelope(SoapEnvelope.VER11);
    envelope.dotNet = true;
    envelope.setOutputSoapObject(request);

    HttpTransport httpTransport = new HttpTransport(SOAP_ADDRESS);
    Object response=null;
    try
    {
    httpTransport.call(SOAP_ACTION, envelope);
    response = envelope.getResponse();
    }
    catch (Exception exception)
    {
    response=exception.toString();
    }
    return response.toString();
    }
}

这是我的Activity点击方法

public void clickData(View v)
{
    //Intent intent = new Intent(this, DisplayMessageActivity.class);
    EditText et=(EditText) findViewById(R.id.editText1);
    EditText et2=(EditText) findViewById(R.id.editText2);
    TextView tv=(TextView) findViewById(R.id.textView1);

    int a=Integer.parseInt(et.getText().toString());
    int b=Integer.parseInt(et2.getText().toString()); 

    CallSoap cs=new CallSoap();
    tv.setText(cs.Call(a, b));
}

出现错误“不幸的是 App1 已停止”。请帮我..

4

2 回答 2

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对于初学者，也是一种非常好的做法，将调用置于单独的线程中。我这样做：

public void call() {
    Log.d("TAG", "Started call");
    new Thread(new Runnable()
    {
        public void run() {
            Looper.prepare();

            /** UI stuff/ This runs on the main thread to update the UI. This can be used for displaying something like "please wait */

            AppPrefFragment.updateSyncJobsNumber(AppPrefFragment.JOB_START);
            if (AppPrefActivity.context != null) {
                ((Activity) AppPrefActivity.context).runOnUiThread(new Runnable()
                {
                    public void run() {
                        //AppPrefFragment.setSyncPreferenceStatusShowingOngoingJobs();
                        ... show "please wait"
                    }
                });
            }


            /** Actual stuff  that you want to do */

            ... the HttpCall or SOAP etc
        }
    }).start();
}

请注意，返回必须异步处理。

于 2013-10-10T14:17:10.987 回答
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这是由于 android 2.2 之后的 NetworkOnMainThread 异常，您无法在 mainUi 线程中运行长时间运行的操作，例如网络访问，因为 mainUI 线程用于加载 Ui 组件以使您的应用程序流畅高效。您应该使用 AsynTask 类来保持它关闭主线程

于 2012-12-31T18:50:19.690 回答