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我正在对 C++ 进行一些自学,并且正在做一些关于数组、循环等的章节。有很多练习,我引用的那个非常简单。初始化两个两行三列的矩阵。

输出矩阵的内容(按指定格式),然后执行保存在第三个矩阵中的加法。输出完成加法的第三个数组。我的代码有效,但我认为有更好的方法来输出而不是处理每个矩阵元素?鉴于这是练习之前的一章,我正在考虑另一个循环,或者这种方式可以接受吗?

#include <iostream>
#include <string>

using namespace std;

int main()
{
    int amatrix[2][3]=
    {
        {-5, 2, 8},
        {1, 0, 0},
    };

    int bmatrix[2][3]=
    {
        {1, 0, 2},
        {0, 3, -6},
    };

    int cmatrix[2][3]=
    {
        {0, 0, 0},
        {0, 0, 0},
    };

    //add generated matrices
    for (int i = 0; i <= 1; i++)
    {
        for (int j =0; j <= 2; j++)
        {
            cmatrix[i][j]=amatrix[i][j]+bmatrix[i][j];
        }
    }

    //output to screen - NEED ADVICE FROM HERE
    cout << "A= " << endl;
    cout << amatrix[0][0] << ", " << amatrix[0][1] << ", " << amatrix[0][2] << endl;
    cout << amatrix[1][0] << ", " << amatrix[1][1] << ", " << amatrix[1][2] << endl << endl;
    cout << "B= " << endl;
    cout << bmatrix[0][0] << ", " << bmatrix[0][1] << ", " << bmatrix[0][2] << endl;
    cout << bmatrix[1][0] << ", " << bmatrix[1][1] << ", " << bmatrix[1][2] << endl << endl;
    cout << "C= " << endl;
    cout << cmatrix[0][0] << ", " << cmatrix[0][1] << ", " << cmatrix[0][2] << endl;
    cout << cmatrix[1][0] << ", " << cmatrix[1][1] << ", " << cmatrix[1][2] << endl << endl;
}
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1 回答 1

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cout << amatrix[i][j]在 for 循环中

于 2013-03-28T10:44:49.547 回答