0

这是我的代码，注释总结了程序应该做什么。

// This program will read in from a file a number that tells how many
// wages and hours worked the file contain. And then calculates the
// salary
import java.util.*;
import java.text.*;

public class Lab10
{
        public static void main(String[] args)
        {
          // Declare variables
          Scanner scan = new Scanner(System.in);
          DecimalFormat fmt = new DecimalFormat("0.00");
          String name;
          double wages;
          double hoursWorked;
          double salary;
          int numCalculate;
          int EmployeeNumber ;
          int i = 0 ;

          // Read in how many employees the file contains
          EmployeeNumber =scan.nextInt() ;

          // for loop that reads and records the name hoursworked and wages , and prints out the information
          for ( ; i < EmployeeNumber +1; i ++ )
          {
           name = scan.next () ;
           wages = scan.nextDouble() ;
           hoursWorked = scan.nextDouble() ;

           salary = calculateSalary(wages,hoursWorked) ;
           System.out.println(name +" worked " +fmt.format(hoursWorked) + " with a wage of " + "$" +fmt.format(wages) + " and got paid $" +fmt.format(salary) );
          }
          // End of control loop

         } // End of main method

         public static double calculateSalary(double wages, double hoursWorked)
         {
//Declare constants
          final int OVERTIME_BREAK = 40;
          final double OVERTIME_MULTIPLE = 1.5;
          double salary = 0 ;

          //Calculate salary

          if(hoursWorked > OVERTIME_BREAK)
          {
          salary = (hoursWorked - OVERTIME_BREAK) * wages * OVERTIME_MULTIPLE + hoursWorked * wages;
          }
          else
          {
            salary = hoursWorked * wages;
          }
          // Return the salary
           return salary ;

         } // end of calculateSalary method
} // End of Lab10 class

使用此输入文件时：

3
Smith 12.50 25
Jones 25.89 60
Brown 7.86 19.89

我得到了我想要的输出，但最后附加了这条消息：

Exception in thread "main" java.util.NoSuchElementException
    at java.util.Scanner.throwFor(Scanner.java:855)
    at java.util.Scanner.next(Scanner.java:1364)
    at Lab10.main(Lab10.java:32)

有人可以告诉我这意味着什么以及如何解决吗？

4

2 回答 2

2

你循环一个太多次了。

您有 3 名员工，因此应该像这样循环：

for ( ; i < EmployeeNumber; i ++ )
{
    name = scan.next () ;
    ...
 }
于 2013-03-27T15:11:30.307 回答
0

Java 的数组索引从 0 开始，所以如果你有 3 个元素，它们存储在 0、1 和 2 处。正如上面在你的 for 循环中所说，如果你只放 i < EmplyeeNumber 就足够了，而不是 EmployeeNumber + 1。

于 2013-03-27T15:32:14.710 回答