iphone - 使用 performSelector 方法传递两个参数

Question

-(void)application :(UIApplication *)application didReceiveRemoteNotification:(NSDictionary *)userInfo
{

    [self addMessageFromRemoteNotification:userInfo updateUI:NO];

}

我需要在 performSelectorInBackground 方法中运行上述方法。但是有单个对象的选项。如何更改我的代码？

Answer 1

使用 GCD：

-(void)application :(UIApplication *)application didReceiveRemoteNotification:(NSDictionary *)userInfo
{
    dispatch_async(dispatch_get_global_queue(DISPATCH_QUEUE_PRIORITY_DEFAULT, 0), ^{
        [self addMessageFromRemoteNotification:userInfo updateUI:NO];
    });

}

dispatch_async 立即返回，然后该块将在后台异步执行。

Answer 2

无法通过 performSelectorInBackground 传递多个参数。当我遇到问题时，我解决问题的方法是传递一个字典，使用文字 NSDictionary 语法使这变得更容易。

-(void)application :(UIApplication *)application didReceiveRemoteNotification:(NSDictionary *)userInfo
{
    [self performSelectorInBackground:@selector(backgroundMethod:) withObject:@{@"userInfo" : someUserInfoDictionary, @"updateUI" : @(NO)}];
}
-(void)backgroundMethod:(NSDictionary *)params
{
    [self addMessageFromRemoteNotification:params[@"userInfo"] updateUI:[params[@"updateUI"] boolValue]];
}