0

我需要计算一组数据的中位数，所以我创建了一个临时表，并尝试在线关注一些文章，但成功率为零，这就是我正在使用的：

CREATE TABLE #QuizTemp (QuizProfileID INT,Cnt INT,TotalScore INT)

INSERT INTO #QuizTemp
SELECT QuizAnswers.QuizProfileID, COUNT(QuizAnswers.QuizProfileID) AS Cnt, SUM(QuizAnswers.AnsweredYes) As TotalScore 
FROM         QuizAnswers INNER JOIN
                      Quizzes ON QuizAnswers.QuizID = Quizzes.QuizID
WHERE     (Quizzes.PartnerID = 16) 
GROUP BY QuizAnswers.QuizProfileID
HAVING COUNT(QuizAnswers.QuizProfileID)= 5

SELECT COUNT(*) AS CNT, Avg(TotalScore) AS AvgTotalScore  FROM #QuizTemp

DROP TABLE #QuizTemp

平均值效果很好，现在我需要中位数。

4

2 回答 2

1

尝试在 INSERT 上捕获行数，然后使用 ROW_NUMBER() 选择中间的行：

CREATE TABLE #QuizTemp (QuizProfileID INT,Cnt INT,TotalScore INT)
DECLARE @Rows int

INSERT INTO #QuizTemp
SELECT QuizAnswers.QuizProfileID, COUNT(QuizAnswers.QuizProfileID) AS Cnt, SUM(QuizAnswers.AnsweredYes) As TotalScore 
FROM         QuizAnswers INNER JOIN
                      Quizzes ON QuizAnswers.QuizID = Quizzes.QuizID
WHERE     (Quizzes.PartnerID = 16) 
GROUP BY QuizAnswers.QuizProfileID
HAVING COUNT(QuizAnswers.QuizProfileID)= 5


DECLARE @Rows int
SELECT @Rows=@@Rowcount

;with allrows as
(
    SELECT TotalScore, ROW_NUMBER() (ORDER BY TotalScore) AS RowNumber

)
SELECT @Rows AS CNT, TotalScore AS MedianScore
FROM allrows WHERE RowNumber=@Rows/2


DROP TABLE #QuizTemp

编辑

这是一个没有临时表的解决方案：

DECLARE @YourTable  table (TotalScore int)
INSERT INTO @YourTable Values (1)
INSERT INTO @YourTable Values (2)
INSERT INTO @YourTable Values (3)
INSERT INTO @YourTable Values (40)
INSERT INTO @YourTable Values (50)
INSERT INTO @YourTable Values (60)
INSERT INTO @YourTable Values (70)

;with allrows as
(
    SELECT
        TotalScore, ROW_NUMBER() OVER (ORDER BY TotalScore) AS RowNumber
        FROM @YourTable
)
,MaxRows AS
(SELECT MAX(RowNumber) AS CNT,CONVERT(int,ROUND(MAX(RowNumber)/2.0,0)) AS Middle FROM allrows)
SELECT 
    m.CNT
    ,(SELECT AVG(TotalScore) FROM allrows) AS AvgTotalScore  
    ,a.TotalScore AS Median
    ,m.Middle AS MedianRowNumber
    FROM allrows              a
        CROSS JOIN MaxRows    m
    WHERE a.RowNumber=m.Middle

输出：

CNT                  AvgTotalScore        Median      MedianRowNumber
-------------------- -------------------- ----------- --------------------
7                    32                   40          4

(1 row(s) affected)

如果您将第一个 CTE 编辑为：

;with allrows as
(
    SELECT QuizAnswers.QuizProfileID, COUNT(QuizAnswers.QuizProfileID) AS Cnt, SUM(QuizAnswers.AnsweredYes) As TotalScore 
    , ROW_NUMBER() OVER (ORDER BY TotalScore) AS RowNumber
    FROM         QuizAnswers INNER JOIN
                          Quizzes ON QuizAnswers.QuizID = Quizzes.QuizID
    WHERE     (Quizzes.PartnerID = 16) 
    GROUP BY QuizAnswers.QuizProfileID
    HAVING COUNT(QuizAnswers.QuizProfileID)= 5
)

它应该适用于您的查询

于 2009-10-13T17:32:45.267 回答
0

但是，数值的中值通常已经结束。只需使用此示例：

DECLARE @testTable TABLE 
( 
    VALUE   INT
)
--INSERT INTO @testTable -- Even Test
--SELECT 3 UNION ALL
--SELECT 5 UNION ALL
--SELECT 7 UNION ALL
--SELECT 12 UNION ALL
--SELECT 13 UNION ALL
--SELECT 14 UNION ALL
--SELECT 21 UNION ALL
--SELECT 23 UNION ALL
--SELECT 23 UNION ALL
--SELECT 23 UNION ALL
--SELECT 23 UNION ALL
--SELECT 29 UNION ALL
--SELECT 40 UNION ALL
--SELECT 56

--
--INSERT INTO @testTable -- Odd Test
--SELECT 3 UNION ALL
--SELECT 5 UNION ALL
--SELECT 7 UNION ALL
--SELECT 12 UNION ALL
--SELECT 13 UNION ALL
--SELECT 14 UNION ALL
--SELECT 21 UNION ALL
--SELECT 23 UNION ALL
--SELECT 23 UNION ALL
--SELECT 23 UNION ALL
--SELECT 23 UNION ALL
--SELECT 29 UNION ALL
--SELECT 39 UNION ALL
--SELECT 40 UNION ALL
--SELECT 56


DECLARE @RowAsc TABLE
(
    ID      INT IDENTITY,
    Amount  INT
)

INSERT INTO @RowAsc
SELECT  VALUE 
FROM    @testTable 
ORDER BY VALUE ASC

SELECT  AVG(amount)
FROM @RowAsc ra
WHERE ra.id IN
(
    SELECT  ID 
    FROM    @RowAsc
    WHERE   ra.id -
    (
        SELECT  MAX(id) / 2.0 
        FROM    @RowAsc
    ) BETWEEN 0 AND 1

)
于 2011-06-13T13:07:23.250 回答