1

我正在尝试使用会话变量中的用户 user_id 将上传的图像插入 mysql。我找到了一个在线教程并将其更改如下：

<?php
require_once('../Login/includes/session_timeout_db.inc.php');
$dbuser="";
  $dbname="";
  $dbpass="";
  $dbserver="";

  $con = mysql_connect($dbserver,$dbuser,$dbpass);
  if (!$con){ die('Could not connect: ' . mysql_error()); }
  mysql_select_db($dbname, $con);

  // Make sure the user actually
    // selected and uploaded a file
    if (isset($_FILES['image']) && $_FILES['image']['size'] > 0) {

    // Temporary file name stored on the server
    $tmpName = $_FILES['image']['tmp_name'];

    // Read the file
    $fp = fopen($tmpName, 'r');
    $data = fread($fp, filesize($tmpName));
    $data = addslashes($data);
    fclose($fp);


    // Create the query and insert
    // into our database.
    $query = "INSERT INTO images, owner_id";
    $query .= "(image) VALUES ('$data', '.$_SESSION['id'].')";
    $results = mysql_query($query, $link);

// Print results
print "Thank you, your file has been uploaded.";

}
else {
print "No image selected/uploaded";
}

// Close our MySQL Link
mysql_close($link);
?> 

<!DOCTYPE html PUBLIC “-//W3C//DTD XHTML 1.0 Strict//EN”
“http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd”&gt;
<html xmlns=”http://www.w3.org/1999/xhtml”&gt;
<head>
<meta http-equiv=”Content-Type” content=”text/html; charset=utf-8” />
<title>Manage Tasks</title>
<link rel="stylesheet" type="text/css" href="../allcss/style.css" />
</head>

<body>

<?php
require('../Login/includes/header.inc.php');
?>

<div id="content">
<form enctype="multipart/form-data" action="" method="post" name="changer">
<input name="MAX_FILE_SIZE" value="102400" type="hidden">
<input name="image" accept="image/jpeg" type="file">
<input value="Submit" type="submit">
</form>
</div>

</body>
</html>

我在查询的第二行遇到错误：

$query = "INSERT INTO images, owner_id";
$query .= "(image) VALUES ('$data', '.$_SESSION['id'].')";
$results = mysql_query($query, $link);

*错误是解析错误：语法错误，意外的 T_ENCAPSED_AND_WHITESPACE，在第 28 行需要 T_STRING 或 T_VARIABLE 或 T_NUM_STRING*

有人可以帮忙吗？

提前致谢

4

2 回答 2

3

您的images字段需要是BLOB类型。但是不要这样做，将文件保存在文件系统中并将目录路径保存到数据库中的图像。

于 2013-03-24T14:04:24.763 回答
1

改变 ：

"(image) VALUES ('$data', '.$_SESSION['id'].')";

进入 ：

"(image) VALUES ('$data', '".$_SESSION['id']."')";
于 2015-08-20T19:17:52.957 回答