我有一个包含数字列表的文本文件。在这种情况下,我想计算每三个数字的平均值。有什么想法吗?之前谢谢
文本文件中的数字示例:
5
7
3
10
12
6
我想要的输出:
5
9
我有一个包含数字列表的文本文件。在这种情况下,我想计算每三个数字的平均值。有什么想法吗?之前谢谢
文本文件中的数字示例:
5
7
3
10
12
6
我想要的输出:
5
9
data.txt
:
5
7
3
10
12
6
如何使用numpy处理它:
In [4]: import numpy as np
In [5]: with open('data.txt') as f:
data = f.read().split()
...:
In [6]: data
Out[6]: ['5', '7', '3', '10', '12', '6']
In [7]: a = np.array(map(float, data))
In [8]: a
Out[8]: array([ 5., 7., 3., 10., 12., 6.])
In [9]: b = a.reshape([-1,3])
In [10]: b
Out[10]:
array([[ 5., 7., 3.],
[ 10., 12., 6.]])
In [11]: b.sum(1)/3
Out[11]: array([ 5. , 9.33333333])
您需要“解析”文本文件,为此您需要知道它的组织方式和编码方式。我先问你几个问题。
你可以 od 以下
#read the file
my_file = open("C:/numbers.txt",'r')
my_text = my_file.read()
my_file.close()
#get a list of numbers from it (in string form)
my_text_numbers = my_text.split(' ')
#use list comprehension to get integer...also consider
#using map function
my_int_numbers = [int(n) for n in my_text_numbers]
#now the averaging part I will leave to you, I assume it's
#the file reading part you needed help with.
假设它们都在一行:
# text file is myData.txt
averages = {} # using a dictionary so you can keep track of the starting point
with open('myData.txt', 'r') as myFile:
data = myFile.read().split('\n') # this creates a list of the data
for index in range(len(data), 3): # step of 3
n = float(int(data[index]) + int(data[index+1]) + int(data[index+2])) / 3
averages[index] = n
IndexError
如果列表不完全是 3 块,这将引发一个问题,所以我在try
/except
块中添加了:
# text file is myData.txt
averages = {}
with open('myData.txt', 'r') as myFile:
data = myFile.read().split('\n') # this creates a list of the data
for index in range(len(data), 3): # step of 3
try: a = int(data[index])
except (IndexError, TypeError): a = 0
try: b = int(data[index+1])
except (IndexError, TypeError): b = 0
try: c = int(data[index+2])
except (IndexError, TypeError): c = 0
# except (IndexError, TypeError): avoids an error if the end of the list
# has been reached or the line is not an integer
n = float(a + b + c) / 3
averages[index] = n