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I am having a lot of trouble setting up my Xcode project so that it builds on my iPhone.

I have followed all the steps in the Development Provisioning Assistant, but I always end up with a valid provisioning profile matching the application's Identifier 'com.test' could

not be found Error when I build.

My app identifier on the provisioning profile is 93QA3MXYM7.com.test.MediaAccess. In my

info.plist file the bundle identifier is com.test.I have tired pretty much every

combination of 93QA3MXYM7.com.test.MediaAccess that makes sense and I can think of, but I

always get the same error, saying that a provisioning profile doesn't match!

I am very confused as what is the application name, the project name, the bundle name, the

app ID description, the bundle ID, and the bundle seed ID. In the Development Provisioning

Assistant, when you create an AppID, there is only the app description field. When you

create an AppID through the regular interface, there are 3 fields! Which ones should match?

Could I get an example please? thanks!

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1 回答 1

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只需将 com.test.MediaAccess 放入“Bundle identifier”属性即可。然后去选择你项目的设置,找到代码签名身份部分并为你的调试配置选择正确的配置文件(应该下载并设置正确的配置文件)

于 2013-03-21T21:53:11.470 回答