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我有一个这样创建的函数：

create or replace function core.nrt_summary_by_param_id(int) returns table (reason_type_id int, reason_id int, descr varchar(256), num int, pct numeric, cause_rank int) as $$
begin
    return query
        with r3 as (
            //A bunch of queries
        )
        select
            r3.reason_type_id,
            r3.reason_id, 
            r3.desc, 
            r3.num, 
            r3.pct,
            r3.cause_rank
        from r3;
        where
            r3.param_id = $1
    return;
end
$$ language plpgsql;

当我这样调用函数时：

select nrt_summary_by_param_id(5);

结果是这样的：

              nrt_summary_by_param_id  
----------------------------------------------------  
 (1,2001,"A",14,19.72,1)  
 (1,2006,"B",9,12.68,2)
 (1,2202,"C",8,11.27,3)
 (1,2002,"D",8,11.27,3)
 (1,2302,"E",7,9.86,5)
 (1,2201,"F",4,5.63,6)
 (1,2206,"G",4,5.63,6)
 (1,2301,"H",2,2.82,8)
 (1,2303,"I",2,2.82,8)
 (1,2005,"J",2,2.82,8)
 (1,2004,"K",2,2.82,8)
 (1,2204,"L",2,2.82,8)
 (,,"M",7,9.87,11)
 (13 rows)

如何从我的函数中获得包含多列的表的返回？如何让每个单独的列显示？如果函数内部的整个查询是从命令行正常执行的，我希望返回是这样的。谢谢！

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1 回答 1

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如果您的函数返回一个表格，那么您应该将其视为表格。我们通常如何查看 SQL 中的表？我们从他们中选择……。您正在寻找更像这样的东西：

select ...
from nrt_summary_by_param_id(5);
于 2013-03-21T15:57:16.150 回答