我正在使用这个:
$t = "#hashtag #goodhash_tag united states #l33t this";
$queryVariable = "";
if(preg_match_all('/(^|\s)(#\w+)/', $t, $arrHashTags) > 0){
array_filter($arrHashTags);
array_unique($arrHashTags);
$count = count($arrHashTags[2]);
if($count > 1){
$counter = 1;
foreach ($arrHashTags[2] as $strHashTag) {
if (preg_match('/#\d*[a-z_]+/i', $strHashTag)) {
if($counter == $count){
$queryVariable .= $strHashTag;
} else{
$queryVariable .= $strHashTag." and ";
}
$newTest = str_replace($arrHashTags[2],"", $t);
}
$counter = $counter + 1;
}
}
}
echo $queryVariable."<br>"; // this is list of tags
echo $newTest; // this is the remaining text
基于$t
以上的输出是:
#hashtag and #goodhash_tag and #l33t
united states this
第一个问题:
如果$t = '#hashtag#goodhash_tag united states #l33t this';
即两个标签之间没有空格,则输出变为:
#hashtag and #l33t
#goodhash_tag united states this
第二个问题:
如果$t = '#hashtag #goodhash_tag united states #l33t this #123';
即带有无效标签#123
,它会以某种方式干扰我提取的标签列表,$queryVariable
就像输出一样
#hashtag and #goodhash_tag and #l33t and // note the extra 'and'
united states this
如果有人请帮助这两个?