iphone - 如何从 NSString 解析数字？

Question

NSString *numberVector = @"( 1, 2, 3, 4)";

我想从这些数字中获取 NSMutableArray。我怎样才能做到这一点？

Answer 1

这是更简单的一个，先将其转换为 json 字符串，然后转换为数组使用NSJSONSerialization

NSString *numberVector = @"( 1, 2, 3, 4)";
numberVector = [numberVector stringByReplacingOccurrencesOfString:@"(" withString:@"["];
numberVector = [numberVector stringByReplacingOccurrencesOfString:@")" withString:@"]"];
NSError* error;
NSMutableArray *arr = [NSJSONSerialization JSONObjectWithData:[numberVector dataUsingEncoding:NSUTF8StringEncoding] options:NSJSONReadingMutableContainers error:&error];

更新

这对两者都有效@"( 1, 2, 3, 4)"，@"(\n 1,\n 2,\n 3,\n 4\n)"因为 json 字符串可以有新行和空格。

PS这适用于 iOS 5.0 或更高版本的其他 iOS，您可以使用 SBJSON 或其他可用的解析库。

Answer 2

如果您知道这正是您的格式，并且不必在空格、括号或逗号的数量上保持灵活：

NSCharacterSet *trimSet = [NSCharacterSet characterSetWithCharactersInString:@" ()"];
numberVector = [numberVector stringByTrimmingCharactersInSet:trimSet];
NSArray *numbers = [numberVector componentsSeparatedByString:@", "];

Answer 3

像这样尝试它对于它只接受数字的任何类型的数据都可以正常工作。

NSString *numberVector = @"(\n 1,\n 2,\n 3,\n 4\n)";

    NSString *onlyNumbers = [numberVector  stringByReplacingOccurrencesOfString:@"[^0-9,]" withString:@"" options:NSRegularExpressionSearch range:NSMakeRange(0, [numberVector  length])];
    NSArray *numbers=[onlyNumbers componentsSeparatedByString:@","];
    NSLog(@"%@",numbers);

Answer 4

请参阅下面的代码，它应该可以工作：

  NSCharacterSet *cSet = [NSCharacterSet characterSetWithCharactersInString:@" ()"];  
  numberVector = [numberVector stringByTrimmingCharactersInSet:cSet];
  //specify delimiter below
  NSArray *numbers = [numberVector componentsSeparatedByString:@", "];

Answer 5

有了这个：

NSString *numberVector = @"( 1, 2, 3, 4)";

编辑

NSError *error = NULL;
NSRegularExpression *regex = [NSRegularExpression regularExpressionWithPattern:@"&([^;])*;" options:NSRegularExpressionCaseInsensitive error:&error];
NSString *modifiedString = [numberVector stringByReplacingMatchesInString:string options:0 range:NSMakeRange(0, [string length]) withTemplate:@""];

NSArray *listItems = [[modifiedString stringByTrimmingCharactersInSet:[NSCharacterSet newlineCharacterSet]] componentsSeparatedByString:@", "]