sql - 使用 LEFT JOIN 删除

Question

我想根据引用第一个的另一个表上存在的数据从一个表中删除，但是，我的代码可以工作并显示当我将其作为 SELECT 语句运行时要删除的值，但是当我将其更改为DELETE 它给了我错误，我不明白他们为什么在那里。

DELETE leadCustomer.* FROM coursework.leadCustomer LEFT JOIN coursework.flightBooking
ON leadCustomer.customerID = flightBooking.customerID
WHERE leadCustomer.customerID NOT IN (
SELECT customerID FROM (SELECT customerID, status FROM coursework.flightBooking) AS
StatusCount where status IN  ('R','H') GROUP BY customerID
)
AND leadCustomer.customerID = 8;

错误：

ERROR:  syntax error at or near "leadCustomer"
LINE 1: DELETE leadCustomer.* FROM coursework.leadCustomer LEFT JOIN...
               ^

********** Error **********

ERROR: syntax error at or near "leadCustomer"
SQL state: 42601
Character: 8

我正在使用 postgres

Answer 1

样本。删除表 'A' 中的记录 表 'H' 中没有记录

DELETE A FROM ARTICULO_ALMACEN A
LEFT JOIN HISTORICO_UNION H
ON A.COD_ARTICULO = H.COD_ARTICULO
AND A.COD_ALMACEN = H.COD_ARTICULO_ALMACEN
AND A.TPROPIEDAD1 = H.PROPIEDAD1
AND A.TPROPIEDAD2 = H.PROPIEDAD2
AND A.TPROPIEDAD3 = H.PROPIEDAD3
WHERE H.COD_ARTICULO IS NULL

Answer 2

从我看到的地方，您实际上并不需要加入来执行此操作...

DELETE FROM coursework.leadCustomer 
WHERE leadCustomer.customerID NOT IN (
SELECT distinct customerID FROM coursework.flightBooking  where status IN  ('R','H') 
)
AND leadCustomer.customerID = 8;

它将删除leadcustomer 中的所有记录，其customerID 为：1）不同于8 2）不在表航班预订中，状态为“R”或“H”

这不是你想要做的吗？

Answer 3

您将需要这样做：

从 TableA 中删除 ID in（从 tableA 中选择 ID a left outer join tableB b on a.ID = b.ID where b.ID is NULL）

Answer 4

.*从leadCustomer.* 即删除：

DELETE leadCustomer FROM coursework.leadCustomer LEFT JOIN coursework.flightBooking
ON leadCustomer.customerID = flightBooking.customerID
WHERE leadCustomer.customerID NOT IN (
SELECT customerID FROM (SELECT customerID, status FROM coursework.flightBooking) AS
StatusCount where status IN  ('R','H') GROUP BY customerID
)
AND leadCustomer.customerID = 8;

Answer 5

you can try this

 DELETE leadCustomer FROM coursework.leadCustomer lc
 LEFT JOIN coursework.flightBooking fb ON lc.customerID = fb.customerID 
 and status IN  ('R','H')and fb.customer_id is not null
 WHERE  leadCustomer.customerID = 8;