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我想提取与每个建筑月组合中 var1 的最小值相对应的 var2 的值。这是我的（假）数据集：

 head(mydata)

 #  building month      var1     var2
 #1        A     1 -26.96333 376.9633
 #2        A     1 165.38759 317.3993
 #3        A     1  47.46345 271.0137
 #4        A     2  73.47784 294.8171
 #5        A     2 107.80130 371.7668
 #6        A     2  10.16384 308.7975

可重现的代码：

## create fake data set:
set.seed(142)
mydata1 = data.frame(building = rep(LETTERS[1:5],6),month = sort(rep(1:6,5)),var1=rnorm(30,50,35),var2 = runif(30,200,400))
mydata2 = data.frame(building = rep(LETTERS[1:5],6),month = sort(rep(1:6,5)),var1=rnorm(30,60,35),var2 = runif(30,150,400))
mydata3 = data.frame(building = rep(LETTERS[1:5],6),month = sort(rep(1:6,5)),var1=rnorm(30,40,35),var2 = runif(30,250,400))
mydata = rbind(mydata1,mydata2,mydata3)
mydata = mydata[ order(mydata[,"building"], mydata[,"month"]), ]
row.names(mydata) = 1:nrow(mydata)

## here is how I pull the minimum value of v1 for each building-month combination:
require(reshape2)
m1 = melt(mydata, id.var=1:2)
d1 = dcast(m1, building ~ month, function(x) min(max(x,0), na.rm=T),
           subset = .(variable == "var1"))

这会为每个建筑月组合提取 var1 的最小值......

head(d1)

#  building         1         2        3         4         5         6
#1        A 165.38759 107.80130 93.32816  73.23279  98.55546 107.58780
#2        B  92.08704  98.94959 57.79610  94.10530  80.86883  99.75983
#3        C  93.38284 100.13564 52.26178  62.37837  91.98839  97.44797
#4        D  82.43440  72.43868 66.83636 105.46263 133.02281  94.56457
#5        E  70.09756  61.44406 30.78444  68.24334  94.35605  61.60610

但是，我想要的是一个与 d1 完全相同的数据框，它显示 var2 的值，该值对应于拉取的最小值var1（如上所示d1）。我的直觉告诉我它应该是 的变体which.min()，但还没有让它与dcast()or一起使用ddply()。任何帮助表示赞赏！

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1 回答 1

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一步可能有可能，但我对 plyr 比 reshape2 更熟悉，

dcast(ddply(mydata, .(building, month), summarize, value = var2[which.min(var1)]), 
      building ~ month)
于 2013-03-17T18:36:57.147 回答