我必须比较 XML 中的两个文件，其中我需要显示文件之间“不匹配模式”的内容，无论是节点名称还是节点值的差异。
到目前为止我写的代码是
using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Xml;
using System.Xml.XPath;
namespace ConsoleApplication1
{
public class Program
{
public Program()
{
XmlDocument _mxml1 = new XmlDocument();
_mxml1.Load(@"C:\Users\Rahul\Documents\xml work\abcd.xml");
XmlDocument _mxml2 = new XmlDocument();
_mxml2.Load(@"C:\Users\Rahul\Documents\xml work\efg.xml");
XmlElement _melement1 = _mxml1.DocumentElement;
XmlElement _melement2 = _mxml2.DocumentElement;
XPathNavigator nav1 = _mxml1.CreateNavigator();
XPathNavigator nav2 = _mxml2.CreateNavigator();
if (_melement1.HasChildNodes && _melement2.HasChildNodes && _melement1.ChildNodes.Count == _melement2.ChildNodes.Count)
{
XmlNodeList _node1 = _melement1.ChildNodes;
XmlNodeList _node2 = _melement2.ChildNodes;
foreach (XmlNode _n1 in _node1)
{
foreach (XmlNode _n2 in _node2)
{
int count = _n1.ChildNodes.Count;
int count2 = _n2.ChildNodes.Count;
if (_n1.Name.ToString() == _n2.Name.ToString())
{
int res = _n1.OuterXml.CompareTo(_n2.OuterXml);
if (res == 1)
{
Console.WriteLine("All the child names match for the case ");
}
if (_n1.InnerText.ToString() != _n2.InnerText.ToString())
{
Console.WriteLine("Values of some child doesnot match");
// here we need to traverse through child nodes of both xmls to find out the change in file..
}
if (_n1.InnerXml.ToString() == _n2.InnerXml.ToString())
{
Console.WriteLine("Records match completly");
}
}
else
{
Console.WriteLine("XML_1 " + " " + "" + "XML_2 \n" + _n1.Name + " " + _n2.Name);
}
}
}
}
}
static void Main(string[] args)
{
Program obj = new Program();
}
}
}
现在的问题是如果节点的值存在差异，如何找到两个文件中不同的字符串部分......