8

我需要找出有多少人在 3 个不同年份（2006 年、2007 年、2008 年）的 60 天内、120 天内、180 天内、180 天内提交了 (fil_dt) 纳税申报表

下面的陈述将给我所有年份，我需要计算每年和每种可能性..无论如何我可以在没有 2 个查询的情况下做到这一点？

SELECT YEAR(A.FPE) AS "YEAR"
,CASE                                              
  WHEN DAYS(A.FIL_DT) - DAYS(A.FPE) < 60 THEN '2 ' 
  WHEN DAYS(A.FIL_DT) - DAYS(A.FPE) < 120 THEN '4 '
  WHEN DAYS(A.FIL_DT) - DAYS(A.FPE) < 180 THEN '6 '
  WHEN DAYS(A.FIL_DT) - DAYS(A.FPE) > 180 THEN '6+'
 END AS "NBR MTH"                                  
WHERE A.FPE BETWEEN '2006-01-01' AND '2008-12-31'

我需要你的帮助非常感谢

4

4 回答 4

22

然后写

   SELECT YEAR(A.FPE) AS "YEAR",
       Sum(CASE WHEN DAYS(A.FIL_DT) - DAYS(A.FPE) < 60 
                  THEN 1 Else 0 End) SixtydayCount,  
       Sum(CASE WHEN DAYS(A.FIL_DT) - DAYS(A.FPE) < 120 
                  THEN 1 Else 0 End) OneTwentyDayCount,
       Sum(CASE WHEN DAYS(A.FIL_DT) - DAYS(A.FPE) < 180 
                  THEN 1  Else 0 End) OneEightyDayCount,
       Sum(CASE WHEN DAYS(A.FIL_DT) - DAYS(A.FPE) > 180 
                  THEN 1 Else 0 End)  OverOneEightyCount  
    From Table A
    WHERE A.FPE BETWEEN '2006-01-01' AND '2008-12-31'
    Group By YEAR(A.FPE)

如果您希望 120 天计数和 180 天计数仅包括 60 岁以上和 120 岁以下的人等，那么，

     SELECT YEAR(A.FPE) AS "YEAR",
       Sum(CASE WHEN DAYS(A.FIL_DT) - DAYS(A.FPE) < 60 
                  THEN 1 Else 0 End) SixtydayCount,  
       Sum(CASE WHEN DAYS(A.FIL_DT) - DAYS(A.FPE) Between 60 And 119 
                  THEN 1 Else 0 End) OneTwentyDayCount,
       Sum(CASE WHEN DAYS(A.FIL_DT) - DAYS(A.FPE) Between 120 And 179 
                  THEN 1  Else 0 End) OneEightyDayCount,
       Sum(CASE WHEN DAYS(A.FIL_DT) - DAYS(A.FPE) >= 180 
                  THEN 1 Else 0 End)  OverOneEightyCount  
    From Table A
    WHERE A.FPE BETWEEN '2006-01-01' AND '2008-12-31'
    Group By YEAR(A.FPE)
于 2009-10-08T14:44:07.737 回答
3 
SELECT  CASE
        WHEN DAYS(A.FIL_DT) - DAYS(A.FPE) < 60 THEN '2 ' 
        WHEN DAYS(A.FIL_DT) - DAYS(A.FPE) < 120 THEN '4 '
        WHEN DAYS(A.FIL_DT) - DAYS(A.FPE) < 180 THEN '6 '
        WHEN DAYS(A.FIL_DT) - DAYS(A.FPE) > 180 THEN '6+'
        END AS NBR_MTH,
        y,
        COUNT(a.fpe)
FROM    (
        SELECT  2006 AS y
        UNION ALL
        SELECT  2007 AS y
        UNION ALL
        SELECT  2008 AS y
        )
LEFT JOIN
        A
ON      A.FPE >= CAST(CONCAT(y, '-01-01') AS DATETIME)
        AND a.FPE < CAST(CONCAT(y + 1, '-01-01') AS DATETIME)
GROUP BY
        y, mbr_mth

与 simple 不同GROUP BY YEAR()，这甚至会选择0丢失的记录（例如，如果 中没有6+记录2008）

于 2009-10-08T14:43:35.447 回答
2

按您的案例陈述所代表的列分组：

SELECT 
  YEAR(A.FPE) AS "YEAR",
  CASE                                              
    WHEN DAYS(A.FIL_DT) - DAYS(A.FPE) < 60 THEN '2 ' 
    WHEN DAYS(A.FIL_DT) - DAYS(A.FPE) < 120 THEN '4 '
    WHEN DAYS(A.FIL_DT) - DAYS(A.FPE) < 180 THEN '6 '
    WHEN DAYS(A.FIL_DT) - DAYS(A.FPE) > 180 THEN '6+'
  END AS "NBR MTH",
  COUNT(1) AS "TOTAL"
FROM Table
WHERE 
  A.FPE BETWEEN '2006-01-01' AND '2008-12-31'
GROUP BY
  "YEAR",
  "NBR MTH"

此查询将为您提供每个唯一年份/“NBR MTH”组合的每条记录的计数。

于 2009-10-08T14:39:14.113 回答
1

实际上，大多数 DBMS 不允许 GROUP BY 使用别名，所以它必须是

...
GROUP BY 
  YEAR(A.FPE),
  CASE                                              
    WHEN DAYS(A.FIL_DT) - DAYS(A.FPE) < 60 THEN '2 ' 
    WHEN DAYS(A.FIL_DT) - DAYS(A.FPE) < 120 THEN '4 '
    WHEN DAYS(A.FIL_DT) - DAYS(A.FPE) < 180 THEN '6 '
    WHEN DAYS(A.FIL_DT) - DAYS(A.FPE) > 180 THEN '6+'
  END
于 2009-10-08T14:42:34.870 回答