iphone - 微小的 url 正在停止功能工作

Question

如果链接被小 url 或类似的东西缩短，我怎样才能让这个功能工作？它似乎首先通过微型 url 服务器，从而导致无法读取与谷歌相关的关键字。

  -(BOOL) webView:(UIWebView *)inWeb shouldStartLoadWithRequest:(NSURLRequest *)inRequest{ NSRange nameRange = [[inRequest.URL absoluteString] rangeOfString:@"google" options:NSCaseInsensitiveSearch];

if(nameRange.location == NSNotFound)
{
    [[UIApplication sharedApplication] openURL:[inRequest URL]];
    return NO;
}
return YES;
}

Answer 1

你为什么不尝试删除if ( inType == UIWebViewNavigationTypeLinkClicked )条件，这样你就可以在 url 中抓住重定向。请参见下面的代码。

 -(BOOL) webView:(UIWebView *)inWeb shouldStartLoadWithRequest:(NSURLRequest *)inRequest navigationType:(UIWebViewNavigationType)inType {
    if ([[inRequest.URL absoluteString] rangeOfString:@"google"].location==NSNotFound){
    [[UIApplication sharedApplication] openURL:[inRequest URL]];
        return NO;
    }
    return YES;
}

Answer 2

用这个

NSRange nameRange = [[inRequest.URL absoluteString] rangeOfString:@"google" options:NSCaseInsensitiveSearch];

            if(nameRange.location == NSNotFound)
            {
                [[UIApplication sharedApplication] openURL:[inRequest URL]];
                return NO;
            }