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我想知道下面的代码是否有替代方法,因为,1:有错误,2:我不想经常这样做:

restring=string.replace("a","01").replace("b","02")...

可能替换的代码:

chars=["a","b","c","d","e","f","g","h","i","j","k","l","m","n","o","p","q","r","t","s","u","v","w","x","y","z"]
numbs=["01","02","03","04","05","06","07","08","09","10","11","12","13","14","15","16","17","18","19","20","21","22","23","24","25","26"]
string="test";
restring=string.replace(chars,numbs);
print restring;
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1 回答 1

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在这里,由于您只有 1 个字符替换“键”,我将使用 dict 和join

>>> chars=["a","b","c","d","e","f","g","h","i","j","k","l","m","n","o","p","q","r","t","s","u","v","w","x","y","z"]
>>> numbs=["01","02","03","04","05","06","07","08","09","10","11","12","13","14","15","16","17","18","19","20","21","22","23","24","25","26"]
>>> d = dict(zip(chars,numbs))
>>> my_sentence = "foobar"
>>> ''.join(d.get(c,c) for c in my_sentence)
'061515020118'

虽然这不能扩展到多个字符替换键......

于 2013-03-08T20:36:39.217 回答