5

我有一个存储纬度和经度的地点数据库。我想查询数据库以查找$requestedDistance特定纬度 ( $latitude) 和经度 ( $longitude) 的半径 ( ) 内的所有地点。

下面的查询有效并仅返回此半径内的那些地方，但是我将如何按距离对它们进行排序，以便最接近的是第一个？过去，我使用原始 SQL 在 SELECT 语句中完成了计算并将其设置为“距离”，然后使用HAVING distance < $requestedDistance ORDER BY distance了，但是我不确定如何使用 Doctrine Repository 将计算添加到 SELECT 查询中。 

$d = $this->getDoctrine()->getRepository('XXXWebsiteBundle:Locations')->createQueryBuilder('l');
        $d
            ->add('where','l.enabled = 1')
            ->andWhere('( 3959 * acos( cos( radians('.$latitude.') )
                * cos( radians( l.latitude ) )
                * cos( radians( l.longitude )
                - radians('.$longitude.') )
                + sin( radians('.$latitude.') )
                * sin( radians( l.latitude ) ) ) ) < '.$requestedDistance);

       $result= $d->getQuery();

更新

感谢@Lazy Ants，我尝试了以下查询：

$d = $this->getDoctrine()->getRepository('XXXWebsiteBundle:Locations')->createQueryBuilder('l');
    $d
        ->select('l')
        ->addSelect(
            '( 3959 * acos(cos(radians(' . $latitude . '))' .
                '* cos( radians( l.latitude ) )' .
                '* cos( radians( l.longitude )' .
                '- radians(' . $longitude . ') )' .
                '+ sin( radians(' . $latitude . ') )' .
                '* sin( radians( l.latitude ) ) ) ) as distance'
        )
        ->andWhere('l.enabled = :enabled')
        ->setParameter('enabled', 1)
        ->andWhere('distance < :distance')
        ->setParameter('distance', $requestedDistance)
        ->orderBy('distance', 'ASC');

但是，它返回以下错误：

`An exception occurred while executing 'SELECT COUNT(*) AS dctrn_count FROM 
(SELECT DISTINCT il0 FROM (SELECT l0_.id AS il0, l0_.name AS name2, l0_.address1 
AS address14, l0_.address2 AS address25, l0_.postcode AS postcode6, l0_.town AS 
town7, l0_.county AS county8, l0_.enabled AS enabled11, l0_.date_created AS 
date_created12, l0_.date_modified AS date_modified13, l0_.latitude AS 
latitude19, l0_.longitude AS longitude20, 3959 * ACOS(COS(RADIANS(53.51331889999999)) 
* COS(RADIANS(l0_.latitude)) * COS(RADIANS(l0_.longitude) - 
RADIANS(-2.935331099999985)) + SIN(RADIANS(53.51331889999999)) * 
SIN(RADIANS(l0_.latitude))) AS sclr21 FROM locations l0_ WHERE l0_.enabled = ? 
AND sclr21 < ? ORDER BY sclr21 ASC) dctrn_result) dctrn_table' with params 
{"1":1,"2":30}:

SQLSTATE[42S22]: Column not found: 1054 Unknown column 'sclr21' in 'where clause'`
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2 回答 2

5 
    $d = $this->getDoctrine()->getRepository('XXXWebsiteBundle:Locations')->createQueryBuilder('l');
    $d
        ->select('l')
        ->addSelect(
            '( 3959 * acos(cos(radians(' . $latitude . '))' .
                '* cos( radians( l.latitude ) )' .
                '* cos( radians( l.longitude )' .
                '- radians(' . $longitude . ') )' .
                '+ sin( radians(' . $latitude . ') )' .
                '* sin( radians( l.latitude ) ) ) ) as distance'
        )
        ->andWhere('l.enabled = :enabled')
        ->setParameter('enabled', 1)
        ->having('distance < :distance')
        ->setParameter('distance', $requestedDistance)
        ->orderBy('distance', 'ASC');
于 2013-03-07T09:59:19.840 回答
0

您正在使用没有 where() 的 andWhere()。

将 andWhere() 替换为 where()。

如果某些属性映射到名为“sclr21”的列上，请同时检查您的实体定义，以便您还可以发现哪个属性有问题。

于 2013-07-12T12:10:44.227 回答