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我正在尝试将字符串分配给新的联系电话号码。

              alert(email +"" + brokerNombre+ "" + phoneNumber);
            var myContact = navigator.contacts.create();
            myContact.displayName = "Hi";
            myContact.phoneNumbers = [phoneNumber];

设置 .phoneNumbers 会导致：

2013-03-04 08:58:35.294 Concierge [6489:c07] * 由于未捕获的异常“NSUnknownKeyException”而终止应用程序，原因：“[<__NSCFString 0xa24af10> valueForUndefinedKey:]：此类不符合键值编码核心价值。' * First throw call stack: (0x14f012 0x26bae7e 0x1d7fb1 0x12a9d1d 0x121600b 0x1215fbd 0x2c5b7 0x2c8bb 0x2cb0c 0x2b12a 0xe7a6 0xfb6c 0x2b65731 0x2b74014 0x2b647d5 0xf5af5 0xf4f44 0xf4e1b 0x34eb7e3 0x34eb668 0x38affc 0x2bfc 0x2b55) libc++abi.dylib: terminate called throwing an exception (lldb)

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1 回答 1

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试试 myContact.phoneNumbers = phoneNumber; 通过删除方括号。

于 2013-03-04T16:46:56.877 回答