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以下是我发布的代码，然后从 url 获取响应...每当我运行代码时，我都没有在 Bufferedreader 中获得响应...

protected Void doInBackground(String... urls) {

    try{

    HttpClient httpclient = new DefaultHttpClient();

    HttpPost httppost = new HttpPost("http://www.indianrail.gov.in/pnr_Enq.html");

    httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs));

     response = httpclient.execute(httppost);

    }catch(Exception e){

    Log.e("log_tag", "Error in http connection "+e.toString());

    }

    return null;

    }


protected void onPostExecute(Void unused) {

    Dialog.dismiss();
    HttpEntity httpEntity= response.getEntity();
    Toast.makeText(getApplicationContext(), "resp of :"+response.getEntity().getContentLength(), Toast.LENGTH_SHORT).show();

    try {
        Toast.makeText(getApplicationContext(), "in", Toast.LENGTH_SHORT).show();
        Toast.makeText(getApplicationContext(), ""+response.getEntity().getContentLength(), Toast.LENGTH_SHORT).show();
        in = new BufferedReader(new InputStreamReader(response.getEntity().getContent()));
        Toast.makeText(getApplicationContext(), "string creating :)",Toast.LENGTH_SHORT).show();
       Toast.makeText(getApplicationContext(), ""+line, Toast.LENGTH_SHORT).show();
    }  catch (Exception e) {
        // TODO Auto-generated catch block
        Toast.makeText(getApplicationContext(), "error", Toast.LENGTH_SHORT).show();

        e.printStackTrace();
    }

我在 postExecute 方法中的 Bufferedreader 出现错误... LogCat o/p 如下

E/ActivityThread(611): Service com.android.exchange.ExchangeService has leaked ServiceConnection com.android.emailcommon.service.ServiceProxy$ProxyConnection@40cf4cf0 that was originally bound here
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1 回答 1

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尝试以下操作：

如果您的响应是 json 格式，请以下列方式使用您的代码，然后使用来自实体的“响应” doInBackground(Void... params)：

DefaultHttpClient client = new DefaultHttpClient();
HttpGet request = new HttpGet(serviceURL);                                   
request.setHeader("Accept", "application/json");
request.setHeader("Content-type", "application/json");
HttpResponse response = client.execute(request);
HttpEntity entity = response.getEntity();

用错误回复你得到的结果..

于 2013-08-21T12:01:41.307 回答