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我写了一个小程序来测试投影阴影是如何工作的。

我想特别检查投影点(可能是三角形的顶点)不位于光源和平面之间而是位于光本身后面的情况,即光位于点和平面之间.

问题是我的小程序甚至在点位于光和平面之间的情况下都不起作用。我检查了数十次计算,所以我猜应该是逻辑错误,但我找不到它..

这里的代码

public class test {

    int x = 0;
    int y = 1;
    int z = 2;
    int w = 3;
    float floor[][] = {
        {-100.0f, -100.0f, 0.0f},
        {100.0f, -100.0f, 0.0f},
        {100.0f, 100.0f, 0.0f},
        {-100.0f, 100.0f, 0.0f}};
    private float shadow_floor[] = new float[16];
    float light_position[] = {0.0f, 0.0f, 10.0f, 1.0f};

    public test() {
        //Find floorplane based on thre known points
        float plane_floor[] = calculatePlane(floor[1], floor[2], floor[3]);

        //store shadowMatrix for floor
        shadow_floor = shadowMatrix(plane_floor, light_position);

        float[] point = new float[]{1.0f, 0.0f, 5.0f, 1.0f};

        float[] projectedPoint = pointFmatrixF(point, shadow_floor);

        System.out.println("point: (" + point[x] + ", " + point[y] + ", " + point[z] + ", "
                + point[w] + ")");
        System.out.println("projectedPoint: (" + projectedPoint[x] + ", " + projectedPoint[y]
                + ", " + projectedPoint[z] + ", " + projectedPoint[w] + ")");
    }

    public static void main(String args[]) {
        test test = new test();
    }

    // make shadow matrix
    public float[] shadowMatrix(float plane[], float light_pos[]) {
        float shadow_mat[] = new float[16];
        float dot;


        dot = plane[x] * light_pos[x] + plane[y] * light_pos[y]
                + plane[z] * light_pos[z] + plane[w] * light_pos[w];

        shadow_mat[0] = dot - light_pos[x] * plane[x];
        shadow_mat[4] = -light_pos[x] * plane[y];
        shadow_mat[8] = -light_pos[x] * plane[z];
        shadow_mat[12] = -light_pos[x] * plane[3];

        shadow_mat[1] = -light_pos[y] * plane[x];
        shadow_mat[5] = dot - light_pos[y] * plane[y];
        shadow_mat[9] = -light_pos[y] * plane[z];
        shadow_mat[13] = -light_pos[y] * plane[w];

        shadow_mat[2] = -light_pos[z] * plane[x];
        shadow_mat[6] = -light_pos[z] * plane[y];
        shadow_mat[10] = dot - light_pos[z] * plane[z];
        shadow_mat[14] = -light_pos[z] * plane[w];

        shadow_mat[3] = -light_pos[w] * plane[x];
        shadow_mat[7] = -light_pos[w] * plane[y];
        shadow_mat[11] = -light_pos[w] * plane[z];
        shadow_mat[15] = dot - light_pos[w] * plane[w];

        return shadow_mat;
    }

    public float[] calculatePlane(float p1[], float p2[], float p3[]) {
        //Array for planlikningen
        float plane[] = new float[4];

        //Gitt to vektorer (tre punkter) i planet kan normalen regnes ut
        //Vi vil ha aboluttverdier
        plane[x] = Math.abs(((p2[y] - p1[y]) * (p3[z] - p1[z])) - ((p2[z] - p1[z])
                * (p3[y] - p1[y])));
        plane[y] = Math.abs(((p2[z] - p1[z]) * (p3[x] - p1[x])) - ((p2[x] - p1[x])
                * (p3[z] - p1[z])));
        plane[z] = Math.abs(((p2[x] - p1[x]) * (p3[y] - p1[y])) - ((p2[y] - p1[y]) 
                * (p3[x] - p1[x])));
        plane[w] = -(plane[x] * p1[x] + plane[y] * p1[y] + plane[z] * p1[z]);


        return plane;
    }

    public float[] pointFmatrixF(float[] point, float[] matrix) {
        int x = 0;
        int y = 1;
        int z = 2;
        float[] transformedPoint = new float[4];

        transformedPoint[x] =
                matrix[0] * point[x]
                + matrix[4] * point[y]
                + matrix[8] * point[z]
                + matrix[12];
        transformedPoint[y] =
                matrix[1] * point[x]
                + matrix[5] * point[y]
                + matrix[9] * point[z]
                + matrix[13];
        transformedPoint[z] =
                matrix[2] * point[x]
                + matrix[6] * point[y]
                + matrix[10] * point[z]
                + matrix[14];
        transformedPoint[w] = 1;

        return transformedPoint;
    }
}

如果平面是 xy 平面,灯光在 (0, 0, 10) 并且点在 (1, 0, 5) 上,那么平面上的投影点应该是 (2, 0, 0),但是程序正在返回 (400000.0, 0.0, 0.0, 1.0)

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1 回答 1

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解决了,我错误地假设投影点的最后一个坐标是 1,但事实并非如此。

https://math.stackexchange.com/questions/320527/projecting-a-point-on-a-plane-through-a-matrix

于 2013-03-06T08:10:22.250 回答