0

我试图结合这两个查询来产生一个百分比值。

SELECT DATEADD(dd, 0, DATEDIFF(dd, 0, regdate)) AS rdate, 
       COUNT(*) as sum 
FROM TBL where regdate > '2013-02-21' 
GROUP BY DATEADD(dd, 0, DATEDIFF(dd, 0, regdate)) 
ORDER BY rdate DESC 

SELECT DATEADD(dd, 0, DATEDIFF(dd, 0, slutdatum)) AS sdate, 
       COUNT(*) as sum 
FROM TBL 
WHERE slutdatum > '2013-02-21' 
GROUP BY DATEADD(dd, 0, DATEDIFF(dd, 0, slutdatum))       
ORDER BY sdate DESC

但我真的不明白。我已经尝试如下所示，但这只会产生错误，这两个查询由它自己工作；（我可以分开运行查询并在获取值后进行数学运算，但这只会导致过度执行）。

SELECT (SELECT DATEADD(dd, 0, DATEDIFF(dd, 0, regdate)) AS rdate, count(*) as sum 
        FROM TBL where regdate > '2013-02-21' 
        GROUP BY DATEADD(dd, 0, DATEDIFF(dd, 0, regdate)) 
        ORDER BY rdate DESC) / (select DATEADD(dd, 0, DATEDIFF(dd, 0, slutdatum)) AS sdate,    
COUNT(*) as sum from TBL where slutdatum > '2013-02-21' 
GROUP BY DATEADD(dd, 0,    
DATEDIFF(dd, 0, slutdatum)) ORDER BY sdate DESC) * 100 from tbl

如何进行一个查询，生成过去 7 天的日期和百分比两列？

4

2 回答 2

1

由于您将比较同一天发生的事件，我们可以在该日期加入，但我们需要FULL OUTER JOIN包括只有休息或只有修复的日子。

这是更新的代码：

SELECT COALESCE(reg.rdate,cl.sdate) as [Date], ISNULL(reg.sum, 0) as [Registered], ISNULL(cl.sum, 0) as [Closed], 
       CASE WHEN cl.sum IS NULL THEN 0
            WHEN ISNULL(cl.sum,0) > ISNULL(reg.sum,0) THEN 100 
            ELSE CONVERT(float,cl.sum)/reg.sum*100 END as [Percentage]  
FROM 

(SELECT regdate AS rdate, COUNT(regdate) as sum 
FROM TBL where regdate > CONVERT(datetime,'20130221',112) 
GROUP BY regdate ) reg 

FULL OUTER JOIN 

(SELECT slutdatum AS sdate, COUNT(slutdatum) as sum 
FROM TBL WHERE slutdatum > CONVERT(datetime,'20130221',112)
GROUP BY slutdatum) cl

ON (reg.rdate=cl.sdate)
ORDER BY COALESCE(reg.rdate,cl.sdate);

我使用测试数据创建了 SQL Fiddle，因此您可以尝试以下代码： http ://sqlfiddle.com/#!3/58a33/1 。

于 2013-03-01T23:48:40.007 回答
0

您可以像使用表格一样使用 (SELECT ...)。所以，试试 SELECT ... FROM (SELECT ...) as A, (SELECT ...) as B

现在您可以在同一个公式中使用 A 和 B 中的值。

于 2013-03-01T23:12:03.213 回答