将 OCMock 对象传递给函数调用 isKindOfClass 的方法。但是对于单元测试,返回的值不是模拟类而是 OCMockObject
问问题
768 次
2 回答
1
这是一整篇文章,解释了如何准确编写该OCMock isKindOfClass
方法(默认情况下不存在)以及如何使用它: http: //blog.carbonfive.com/2009/02/17/custom-constraints-for-ocmock/
于 2013-05-07T09:07:59.753 回答
0
如果要将 OCMock 对象传递给函数调用 isKindOfClass 的方法,则需要创建部分模拟。以下代码可能会对您有所帮助。它对我有用。
-(void)testMyTest
{
FirstViewController* masterVC = [[FirstViewController alloc]init];
SecondViewController *second = [[SecondViewController alloc] init];
id master = [OCMockObject partialMockForObject:second];
[[master expect] getName:@"PARAM"];
[masterVC doSomething:master];
[master verify];
[masterVC release];
[second release];
}
FirstViewController 中的 doSomething 方法
-(void)doSomething:(SecondViewController *)detail
{
if ([detail isKindOfClass:[SecondViewController class]])
{
NSString * returnVal = [detail getName:@"PARAM"];
NSLog(@"returnVal %@",returnVal);
}
}
另一种选择是模拟 isKindOfClass 方法,因此测试用例将变为
- (void)testMyTest
{
CalculatorViewController* masterVC = [[CalculatorViewController alloc]init];
id master = [OCMockObject niceMockForClass:[SecondViewController class]];
BOOL ret = YES;
[[[master expect] andReturnValue:OCMOCK_VALUE(ret)] isKindOfClass:[SecondViewController class]];
[[master expect] getName:@"PARAM"];
[masterVC doSomething:master];
[master verify];
}
于 2013-05-07T08:44:53.057 回答