java - 需要正则表达式帮助 - 拆线

Question

(city = 'pune' AND country = 'india') OR (division = 'it') AND (resource = 'someresource' )

我想根据括号将其分成几组。

第 1 组 -(city = 'pune' AND country = 'india')
第 2 组 -(division = 'it')
第 3 组 -(resource = 'someresource' )

有人可以提供Java中示例的正则表达式吗？

Answer 1

试试这个：（演示：http ://regexr.com?33u8e ）

(\(.+?\))

代码示例（在 PHP 中）：

<?php
     $subject = "(city = 'pune' AND country = 'india') OR (division = 'it') AND (resource = 'someresource' )";
     $pattern = '/(\(.+?\))/';
     preg_match($pattern, $subject, $matches);
     print_r($matches);
?>

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另一种方法：尝试拆分（使用积极的后视）

(?<=\))\s

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编辑：最终答案（Java）

String[] parts = str.split("(?<=\\))\\s");

Answer 2

干得好：\((.+?)\)

string mystring = "(city = 'pune' AND country = 'india') OR (division = 'it') AND (resource = 'someresource' )";
Match results = Regex.Match(mystring, @"\((.+?)\)",RegexOptions.IgnoreCase);

foreach (Group g in results.Groups)
{
    string token = g.Value;
}

现场演示