1

我正在尝试按降序输出名称和相应的分数。有一个字符串数组和另一个整数数组，我试图将这两个数组联系起来。我使用了Arrays.sort并尝试获取索引。然后将使用索引将名称排列在与相应分数相似的位置。我有这段代码，但我得到运行时错误，不幸的是，您的应用程序已停止。任何人都可以帮我做些什么来实现我的目标吗？非常感谢！

           int score[]= new int[4];
            score[0]= 10;
            score[1]= 50;               
            score[2]= 20;
            score[3]= 60;
           String names[] = new String[4];
            names[0]= "player1";
            names[1]= "player2";
            names[2]= "player3";
            names[3]= "player4";

            Arrays.sort(score);
            int index_array[] = new int[4];
            int m = 0;
            for(m = 0; m <4; m++){
                index_array[m]=Arrays.binarySearch(score ,score[m]);
                l = index_array[0];


            }
            for(int i = 0; i<4; i++){
                if(l == score[i]){
                    j = i;
                }
            }
            String name = names[m];
            show.setText(name + " " + Integer.toString(l));
4

3 回答 3

2

您需要关联分数和用户名。目前，您通过数组索引关联它们。当您对分数进行排序时，分数的索引会发生变化。

尝试这样的事情：

class Score implements Comparable<Score>
{
  int score;
  String player;

  public Score(int theScore, String thePlayer)
  {
    score = theScore;
    player = thePlayer;
  }

  public int compareTo(Score)
  {
    ... compare based on the int score value ...
  }

  ... getters.  setters optional ...
}

List<Score> scoreList = new ArrayList<Score>();

... fill scoreList with Score objects. ...

Collections.sort(scoreList);
于 2013-02-25T19:36:59.517 回答
2

创建保存玩家姓名和分数的 Player 模型，然后使用 Comparator 按分数对玩家进行排序。

播放器型号：

class Player {

private String name;

private int score;

public Player(String name, int score) {
    this.name = name;
    this.score = score;
}

public String getName() {
    return name;
}

public int getScore() {
    return score;
}

public String toString() {
    return "name=" + name + "; score=" + score;
}

}

比较器：

class PlayerComparator implements Comparator<Player> {
public int compare(Player p1, Player p2) {
    return p1.getScore() < p2.getScore() ? -1
            : p1.getScore() > p2.getScore() ? 1 : 0;
}

}

以及一个使用示例：

public class PlayerTest {

public static void main(String[] args) {
    int score[]= new int[4];
    score[0]= 10;
    score[1]= 50;
    score[2]= 20;
    score[3]= 60;

    String names[] = new String[4];
    names[0]= "player1";
    names[1]= "player2";
    names[2]= "player3";
    names[3]= "player4";

    Player[] players = new Player[names.length];
    for(int i = 0; i < names.length; i++) {
        players[i] = new Player(names[i], score[i]);
    }

    Arrays.sort(players, new PlayerComparator());

}

}

于 2013-02-25T20:13:40.337 回答
0

这是一种设计气味。你不应该有两个并行数组。相反，您应该有一个 Player 对象数组，其中每个 Player 都有一个名称和一个分数。

按名称或分数存储球员的阵容将非常简单。

Java 是一种面向对象的语言。使用对象。

public class Player
    private final String name;
    private int score;

    public Player(String name, int score) {
        this.name = name;
        this.score = score;
    }

    public String getName() {
        return name;
    }

    public int getScore() {
        return score;
    }

    public void setScore(int score) {
        this.score = score;
    }
}

...
Player[] players = new Player[4];
players[0] = new Player("player1", 10);
...
于 2013-02-25T19:33:23.070 回答