-1 
    String fullWord;
    String firstWord;
    String secondWord;
    String thirdWord;
    String fourthWord;

    int firstPositionOfAsterisk;
    int secondPositionOfAsterisk;
    int thirdPositionOfAsterisk;
    int fullWordCharacters;
    int firstWordCharacters;
    int secondWordCharacters;
    int thirdWordCharacters;
    int fourthWordCharacters;

    char lastLetterFirstWord;


    // I will prompt the user to enter four words seperated by a *
    fullWord = JOptionPane.showInputDialog("Please enter four words: ");

    // I will use the position of the * to make things easier
    firstPositionOfAsterisk = fullWord.indexOf("*");

    firstWord = fullWord.substring(0, firstPositionOfAsterisk);

    secondPositionOfAsterisk = firstWord.indexOf("*");

    secondWord = fullWord.substring(firstPositionOfAsterisk + 1, secondPositionOfAsterisk);

    thirdPositionOfAsterisk = secondWord.indexOf("*");

    thirdWord = fullWord.substring(secondPositionOfAsterisk + 1, thirdPositionOfAsterisk);

    fourthWord = fullWord.substring(thirdPositionOfAsterisk + 1);

    firstWordCharacters = firstWord.length();
    System.out.println(firstWord +" has a length of " + firstWordCharacters + " characters" );


    secondWordCharacters = secondWord.length();
    System.out.println(secondWord +" has length of " + secondWordCharacters + " characters" );

    thirdWordCharacters = thirdWord.length();
    System.out.println(thirdWord +" has length of " + thirdWordCharacters + " characters" );

    fourthWordCharacters = fourthWord.length();
    System.out.println(fourthWord +" has length of " + fourthWordCharacters + " characters" );

    lastLetterFirstWord = firstWord.charAt(firstPositionOfAsterisk - 1);
    System.out.println("The last letter of " + firstWord + "is " + lastLetterFirstWord);

    fullWord = firstWord + secondWord + thirdWord + fourthWord;

    fullWordCharacters = fullWord.length();
    System.out.println(firstWord +", " + secondWord + ", " + thirdWord + ", " + fourthWord + "has length of" + fullWordCharacters);

我试图让用户输入由“*”分隔的 4 个单词，例如 She*will*call*back，我想要这样的输出

她的长度为 3 将的长度为 4 呼叫的长度为 4 回的长度为 4

* 符号位于以下位置：3、8 和 13

她的最后一个字符是s

She, will, call, and back的长度是15

但我不断收到这个 java.lang.StringIndexOutOfBoundsException 错误。我该如何解决？

此行使程序崩溃

secondWord = fullWord.substring(firstPositionOfAsterisk + 1, secondPositionOfAsterisk);

4

2 回答 2

0

简单.. 阅读这个.. String.substring(int, int)

你会看到

throws
   IndexOutOfBoundsException - if the beginIndex is negative, or endIndex is larger than the length of this String object, or beginIndex is larger than endIndex.

重要的部分是或者 beginIndex 大于 endIndex

可能您的secondPositionOfAsterisk值为负 (-1)

于 2013-02-24T00:36:26.520 回答
0 
firstWord = fullWord.substring(0, firstPositionOfAsterisk);

以上将字符串的第一部分直到第一个星号，因此它不会包含星号。所以这将返回-1：

secondPositionOfAsterisk = firstWord.indexOf("*");

那么这将失败：（因为-1不是有效的索引）

secondWord = fullWord.substring(firstPositionOfAsterisk + 1, secondPositionOfAsterisk);

我认为这：

secondPositionOfAsterisk = firstWord.indexOf("*");

应该

int offset = firstWord.length()+1;
secondPositionOfAsterisk = firstWord.indexOf("*", offset);

或类似的东西。

我个人认为String#split是一个更好的选择。

于 2013-02-24T00:40:42.927 回答