8

我有以下情节

require(ggplot2)

dtf <- structure(list(Variance = c(5.213, 1.377, 0.858, 0.613, 0.412, 0.229, 0.139, 0.094, 0.064), Component = structure(1:9, .Label = c("PC1", "PC2", "PC3", "PC4", "PC5", "PC6", "PC7", "PC8", "PC9"), class = "factor")), .Names = c("Variance", "Component"), row.names = c(NA, -9L), class = "data.frame")

ggplot(dtf, aes(x = Component, y = Variance)) +
geom_point()

在此处输入图像描述

我只想用直线连接点。我试过+geom_line()了,但产生了一个错误

4

2 回答 2

27

您的x值是离散的(因子),geom_line()每个唯一x值都被视为单独的组,并尝试仅连接该组内的点。设置确保所有值都被视为一组group=1aes()

ggplot(dtf, aes(x = Component, y = Variance,group=1)) +
  geom_point()+geom_line()
于 2013-02-23T18:25:33.500 回答
0

这将绘制带有 x 的点作为因子类别的整数值:

 ggplot(dtf, aes(x = as.numeric(Component), y = Variance)) +
      geom_point() + geom_line()

您可以使用以下命令放回类别标签:

ggplot(dtf, aes(x = as.numeric(Component), y = Variance)) +
  geom_point() +geom_line() + scale_x_discrete(labels=dtf$Component)
于 2013-02-23T18:39:12.047 回答