iphone - 从提要中填充 UIPickerView

Question

我正在将位置信息解析为NSMutableArray被调用的项目。我填写UIPickerView如下：

- (NSInteger)numberOfComponentsInPickerView:(UIPickerView *)thePickerView {
return 1;
}

- (NSInteger)pickerView:(UIPickerView *)thePickerView numberOfRowsInComponent:(NSInteger)component {
return [items count];
}

- (NSString *)pickerView:(UIPickerView *)thePickerView titleForRow:(NSInteger)row     forComponent:(NSInteger)component {
return [items objectAtIndex:row];
}

-(void)pickerView:(UIPickerView *)pickerView didSelectRow:(NSInteger)row
  inComponent:(NSInteger)component
{
id item = [items objectAtIndex:row];
NSString *occasion = [item objectForKey:@"name"];
location.text = occasion;
}

当我这样做时，UIPickerView 中没有出现任何值，有人可以帮我解决这个问题吗？一切都正确连接

Answer 1

像这样试试

- (NSInteger)numberOfComponentsInPickerView:(UIPickerView *)thePickerView {
    return 1;
}

- (NSInteger)pickerView:(UIPickerView *)thePickerView numberOfRowsInComponent:    (NSInteger)component {
return [items count];
}

- (NSString *)pickerView:(UIPickerView *)thePickerView titleForRow:(NSInteger)row     forComponent:(NSInteger)component {
id item = [items objectAtIndex:row];
NSString *occasion = [item objectForKey:@"name"];
return occasion;
}

-(void)pickerView:(UIPickerView *)pickerView didSelectRow:(NSInteger)row
  inComponent:(NSInteger)component
{
id item = [items objectAtIndex:row];
NSString *occasion = [item objectForKey:@"name"];
location.text = occasion;
}

这将在选择器中显示字符串

还设置了pickerview的代表

我认为您正在传递整个字典而不是字符串

Answer 2

做这些事情：

#1 确保正确设置委托。例如。：

self.pickerView.delegate = self;

#2 检查你的场合字符串是否不为零也不为空。

NSLog(@"%@", occasion);

Answer 3

我猜项目数组可以是字典数组。因此，您应该在 NSDictionary 中获取 NSString。

- (NSString *)pickerView:(UIPickerView *)thePickerView titleForRow:(NSInteger)row     forComponent:(NSInteger)component {
return [[items objectForKey:@"name"] objectAtIndex:row];
}