1

我有三个相互嵌套的无序列表。第二个和第三个ul被隐藏（display: none;）

通过第一个事件，我需要显示第一个的所有ul.second元素。liul.first

通过第二个事件，我需要显示第一个的所有ul.third元素。这是代码：liul.second

HTML

<ul class="first">
<li class="first-element">
    <ul class="second">
        <li class="second-element">
            <ul class="third">
                <li class="third-element"></li>
                <li class="third-element"></li>
                <li class="third-element"></li>
            </ul>
        </li>
        <li class="second-element">
            <ul class="third">
                <li class="third-element"></li>
                <li class="third-element"></li>
                <li class="third-element"></li>
            </ul>
        </li>
        <li class="second-element">
            <ul class="third">
                <li class="third-element"></li>
                <li class="third-element"></li>
                <li class="third-element"></li>
            </ul>
        </li>
    </ul>
</li>
<li class="first-element">
    <ul class="second">
        <li class="second-element">
            <ul class="third">
                <li class="third-element"></li>
                <li class="third-element"></li>
                <li class="third-element"></li>
            </ul>
        </li>
        <li class="second-element">
            <ul class="third">
                <li class="third-element"></li>
                <li class="third-element"></li>
                <li class="third-element"></li>
            </ul>
        </li>
        <li class="second-element">
            <ul class="third">
                <li class="third-element"></li>
                <li class="third-element"></li>
                <li class="third-element"></li>
            </ul>
        </li>
    </ul>
</li>
</ul>

CSS

ul.second li {
    display: none;
}
ul.third li {
    display: none;
}

JS

$('li.first-element:eq(0) li.second-element').show(); // works fine, it shows only li.second-element of ul.first first li
$('li.second-element:eq(0) li.third-element').show(); // does not work, in log it gives me empty []

如何以li.second-element:eq(0) li.third-element其他方式瞄准？

4

1 回答 1

0

然后

$('.first li:eq(0) .second > li');
$('.second > li:eq(0) .third > li');
于 2013-02-22T08:48:23.027 回答