0

我想执行以下操作,但收到错误争论类型DoWindow不可分配给参数System.EventHandler

如何让我的委托继承自System.EventHandler

 public delegate void DoWindow(MdiLayout layoutInstruction) ;

 private ToolStripMenuItem MakeWindowMenu()
    {
        var tsi = new ToolStripMenuItem("Window");
        tsi.DropDownItems.Add(CreateMenuItem("Cascade","Cascade the features",    DoWindowLayout(MdiLayout.Cascade)));
        tsi.DropDownItems.Add(CreateMenuItem("Tile Vertical","Tile the features vertically", this.DoWindowTileVertically));

       //etc
        return tsi;
    }


private   ToolStripMenuItem CreateMenuItem(string Caption, string tooltip, EventHandler onClickEventHandler)
    {
        var item = new ToolStripMenuItem(Caption);
        item.Click += onClickEventHandler;
        item.ToolTipText = tooltip;
        return item;
    }

public DoWindow DoWindowLayout(MdiLayout layoutInstruction)
    {
        Master.MDIForm.LayoutMdi(layoutInstruction);
    }
4

2 回答 2

2

您可以使用 anAction作为参数并使用匿名Eventhandler来调用Action

就像是:

    private ToolStripMenuItem MakeWindowMenu()
    {
        var tsi = new ToolStripMenuItem("Window");
        tsi.DropDownItems.Add(CreateMenuItem("Cascade", "Cascade the features", () => Master.MDIForm.LayoutMdi(MdiLayout.Cascade)));
        tsi.DropDownItems.Add(CreateMenuItem("Tile Vertical", "Tile the features vertically", () => {  }));
        return tsi;
    }

    private ToolStripMenuItem CreateMenuItem(string Caption, string tooltip, Action onClickEventHandler)
    {
        var item = new ToolStripMenuItem(Caption);
        item.Click += (s, e) => { onClickEventHandler.Invoke(); };
        item.ToolTipText = tooltip;
        return item;
    }
于 2013-02-18T21:12:41.807 回答
0

您的自定义事件处理程序需要包含所需的方法签名。换句话说: ToolStripMenuItemClick 需要一个带有签名的方法

delegate void EventHandler(object Sender, EventArgs e);

因此您需要更改委托的签名和相应的方法。

请参阅此处以获取更多参考。

于 2013-02-18T20:54:20.990 回答