例如：
- 一月的第三个星期一 马丁路德金纪念日
- 2 月的第三个星期一 总统日（华盛顿诞辰）
- 三月的最后一个星期日 复活节
- 五月的最后一个星期一为 阵亡将士纪念日
我正在尝试获取这些日期，以便我可以在日历上标记它，而无需手动放置未来几年的所有内容。
修改后的答案！！
$curYir = date("Y");//current year
$MLK = date('Y-m-d', strtotime("january $curYir third monday")); //marthin luthor king day
$PD = date('Y-m-d', strtotime("february $curYir third monday")); //presidents day
$Est = date('Y-m-d', easter_date($curYir))); // easter
$MDay = date('Y-m-d', strtotime("may $curYir first monday")); // memorial day
//("may $curYir last monday") will give you the last monday of may 1967
//much better to determine it by a loop
$eMDay = explode("-",$MDay);
$year = $eMDay[0];
$month = $eMDay[1];
$day = $eMDay[2];
while($day <= 31){
$day = $day + 7;
}
if($day > 31)
$day = $day - 7;
$MDay = $year.'-'.$month.'-'.$day;
$LD = date('Y-m-d', strtotime("september $curYir first monday")); //labor day
$CD = date('Y-m-d', strtotime("october $curYir third monday")); //columbus day
$TH = date('Y-m-d', strtotime("november $curYir first thursday")); // thanks giving
//("november $curYir last thursday") will give you the last thursday of november 1967
//much better to determine it by a loop
$eTH = explode("-",$TH);
$year = $eTH[0];
$month = $eTH[1];
$day = $eTH[2];
while($day <= 30){
$day = $day + 7;
}
if($day > 30)
//watch out for the days in the month November only have 30
$day = $day - 7;
$TH = $year.'-'.$month.'-'.$day;