1

我有以下代码，我的问题是，当我引用变量时，它给了我错误：每个变量的非静态字段、方法或属性都需要对象引用。我知道这与我的 public int 和 public double 是非静态的有关，但我不知道如何解决它。有人可以告诉我吗？

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;

namespace homework3
{
    public class Program
    {

           public int number_of_scores;
           public double score, total_score = 0, high_score, low_score, average;


    } 
    class Class1{

        static void Main(string[] args){


            Console.Write("please enter the number of scores that you
wish to process? ");
            Program.number_of_scores = int.Parse(Console.ReadLine());

            Console.Write("Please enter score " + 1 + " ");
            Program.score = double.Parse(Console.ReadLine());

            Program.high_score = Program.score;
            Program.low_score = Program.score;

            Program.total_score = Program.total_score = Program.score;


            for (int i = 2; i <= number_of_scores; i++);
         }  
 }

     class class2
        {
         static void Main(string[] args){


                Console.Write("Please enter score " + i + " ");
                Program.score = double.Parse(Console.ReadLine());

                Program.total_score = Program.total_score + Program.score;

                if(Program.score > Program.high_score)
                Program.high_score = Program.score;

                if(Program.score < Program.low_score)
                Program.low_score = Program.score;
        }
            }

      class Class3
     {
          static void Main(string[] args){

          Program.average = Program.total_score / Program.number_of_scores;

          Console.WriteLine("you entered " + Program.number_of_scores +
 " scores");
          Console.WriteLine("The high score is " + Program.high_score);
          Console.WriteLine("The low score is " + Program.low_score);
          Console.WriteLine("the average score is " + Program.average);
     }
      }
4

2 回答 2

1

在行中：

Program.number_of_scores = int.Parse(Console.ReadLine());

您尝试从静态方法引用实例变量。number_of_scores

让它工作的最简单的方法是声明number_of_scores为静态的：

static public int number_of_scores;

您的其他一些领域也有同样的问题。

于 2013-02-16T02:57:25.983 回答
1

您需要将 number_of_scores 和 score（以及其他变量）声明为静态的。

public static int number_of_scores;
public static double score, //etc
于 2013-02-16T02:57:54.923 回答