这是您正在寻找的解决方案。这是一个使用颜色参数执行有序抖动 (Bayer) 的 C 函数。它足够快,可以用于实时处理。
#ifndef MIN
#define MIN(a,b) (((a) < (b)) ? (a) : (b))
#endif
#ifndef MAX
#define MAX(a,b) (((a) > (b)) ? (a) : (b))
#endif
#ifndef CLAMP
// This produces faster code without jumps
#define CLAMP( x, xmin, xmax ) (x) = MAX( (xmin), (x) ); \
(x) = MIN( (xmax), (x) )
#define CLAMPED( x, xmin, xmax ) MAX( (xmin), MIN( (xmax), (x) ) )
#endif
const int BAYER_PATTERN_16X16[16][16] = { // 16x16 Bayer Dithering Matrix. Color levels: 256
{ 0, 191, 48, 239, 12, 203, 60, 251, 3, 194, 51, 242, 15, 206, 63, 254 },
{ 127, 64, 175, 112, 139, 76, 187, 124, 130, 67, 178, 115, 142, 79, 190, 127 },
{ 32, 223, 16, 207, 44, 235, 28, 219, 35, 226, 19, 210, 47, 238, 31, 222 },
{ 159, 96, 143, 80, 171, 108, 155, 92, 162, 99, 146, 83, 174, 111, 158, 95 },
{ 8, 199, 56, 247, 4, 195, 52, 243, 11, 202, 59, 250, 7, 198, 55, 246 },
{ 135, 72, 183, 120, 131, 68, 179, 116, 138, 75, 186, 123, 134, 71, 182, 119 },
{ 40, 231, 24, 215, 36, 227, 20, 211, 43, 234, 27, 218, 39, 230, 23, 214 },
{ 167, 104, 151, 88, 163, 100, 147, 84, 170, 107, 154, 91, 166, 103, 150, 87 },
{ 2, 193, 50, 241, 14, 205, 62, 253, 1, 192, 49, 240, 13, 204, 61, 252 },
{ 129, 66, 177, 114, 141, 78, 189, 126, 128, 65, 176, 113, 140, 77, 188, 125 },
{ 34, 225, 18, 209, 46, 237, 30, 221, 33, 224, 17, 208, 45, 236, 29, 220 },
{ 161, 98, 145, 82, 173, 110, 157, 94, 160, 97, 144, 81, 172, 109, 156, 93 },
{ 10, 201, 58, 249, 6, 197, 54, 245, 9, 200, 57, 248, 5, 196, 53, 244 },
{ 137, 74, 185, 122, 133, 70, 181, 118, 136, 73, 184, 121, 132, 69, 180, 117 },
{ 42, 233, 26, 217, 38, 229, 22, 213, 41, 232, 25, 216, 37, 228, 21, 212 },
{ 169, 106, 153, 90, 165, 102, 149, 86, 168, 105, 152, 89, 164, 101, 148, 85 }
};
// This is the ultimate method for Bayer Ordered Diher with 16x16 matrix
// ncolors - number of colors diapazons to use. Valid values 0..255, but interesed are 0..40
// 1 - color (1 bit per color plane, 3 bits per pixel)
// 3 - color (2 bit per color plane, 6 bits per pixel)
// 7 - color (3 bit per color plane, 9 bits per pixel)
// 15 - color (4 bit per color plane, 12 bits per pixel)
// 31 - color (5 bit per color plane, 15 bits per pixel)
void makeDitherBayerRgbNbpp( BYTE* pixels, int width, int height, int ncolors ) noexcept
{
int divider = 256 / ncolors;
for( int y = 0; y < height; y++ )
{
const int row = y & 15; // y % 16
for( int x = 0; x < width; x++ )
{
const int col = x & 15; // x % 16
const int t = BAYER_PATTERN_16X16[col][row];
const int corr = (t / ncolors);
const int blue = pixels[x * 3 + 0];
const int green = pixels[x * 3 + 1];
const int red = pixels[x * 3 + 2];
int i1 = (blue + corr) / divider; CLAMP( i1, 0, ncolors );
int i2 = (green + corr) / divider; CLAMP( i2, 0, ncolors );
int i3 = (red + corr) / divider; CLAMP( i3, 0, ncolors );
// If you want to compress the image, use the values of i1,i2,i3
// they have values in the range 0..ncolors
// So if the ncolors is 4 - you have values: 0,1,2,3 which is encoded in 2 bits
// 2 bits for 3 planes == 6 bits per pixel
pixels[x * 3 + 0] = CLAMPED( i1 * divider, 0, 255 ); // blue
pixels[x * 3 + 1] = CLAMPED( i2 * divider, 0, 255 ); // green
pixels[x * 3 + 2] = CLAMPED( i3 * divider, 0, 255 ); // red
}
pixels += width * 3;
}
}
在您的情况下,您需要使用参数调用函数 ncolors=4 这意味着每个颜色平面(对于灰度它是 1 个平面)将使用每个像素 4 位。
所以,你必须打电话:
makeDitherBayerRgbNbpp( pixels, width, height, 4 );
输入像素为 BGR 格式。出于可视化目的,输出像素也是 BGR 格式。要获取这些位,您必须替换此代码:
pixels[x * 3 + 0] = CLAMPED( i1 * divider, 0, 255 ); // blue
pixels[x * 3 + 1] = CLAMPED( i2 * divider, 0, 255 ); // green
pixels[x * 3 + 2] = CLAMPED( i3 * divider, 0, 255 ); // red
像这样:
out.writeBit( i1 ); // blue
out.writeBit( i2 ); // green
out.writeBit( i3 ); // red
这是带有您的参数的示例图片(4位灰度)
有关更多抖动源代码和演示应用程序,您可以看到这里