我正在编写一个 URL 抓取工具(只是名称和描述),并且正在尝试处理 301 重定向。
现在,我检查标题,如果不是 200,我尝试在标题中找到要重定向到的位置。我的问题出现了,因为 array_search 没有返回 Location 值所在的键,尽管我在那里看到了它。
这是代码片段:
if(strpos($url_headers[0], "200") !== false){
echo "in here";
return $url;
}else{
print_r($url_headers);
//look for location
$location_key = array_search("Location: ", $url_headers);
echo "Location Key: " . $location_key;
$redirect_string = $url_headers[$location_key];
$clean_url = str_replace("Location: ", "", $redirect_string);
return $clean_url;
}
这个的输出是:
Array ( [0] => HTTP/1.0 301 Moved Permanently [1] => Location: http://www.google.com/ [2] => Content-Type: text/html; charset=UTF-8 [3] => Date: Wed, 13 Feb 2013 03:30:00 GMT [4] => Expires: Fri, 15 Mar 2013 03:30:00 GMT [5] => Cache-Control: public, max-age=2592000 [6] => Server: gws [7] => Content-Length: 219 [8] => X-XSS-Protection: 1; mode=block [9] => X-Frame-Options: SAMEORIGIN [10] => HTTP/1.0 200 OK [11] => Date: Wed, 13 Feb 2013 03:30:00 GMT [12] => Expires: -1 [13] => Cache-Control: private, max-age=0 [14] => Content-Type: text/html; charset=ISO-8859-1 [15] => Set-Cookie: PREF=ID=fe86e29432d4e240:FF=0:TM=1360726200:LM=1360726200:S=Wg8VEU7kc7UtcKc-; expires=Fri, 13-Feb-2015 03:30:00 GMT; path=/; domain=.google.com [16] => Set-Cookie: NID=67=KH8Zu8EpKjrhje8nD0lk_868mqvQr9pGwsAsaUuPDD_PRUgohJHoOkdlyYEHWmohUtndyENDJ0oZq8pC1aqOg20anXpUn5btQX5GYM6kYlgMhYxIPajtGp9KymmMDO1Y; expires=Thu, 15-Aug-2013 03:30:00 GMT; path=/; domain=.google.com; HttpOnly [17] => P3P: CP="This is not a P3P policy! See http://www.google.com/support/accounts/bin/answer.py?hl=en&answer=151657 for more info." [18] => Server: gws [19] => X-XSS-Protection: 1; mode=block [20] => X-Frame-Options: SAMEORIGIN ) Location Key: {"error":"invalid_url","error_code":null}
我究竟做错了什么?在抓取用户提供的链接时,是否有更优雅的方式来处理重定向?