c++ - 将字符串数组与用户输入的单个字符串进行比较，它还告诉它在该位置找到了 2 次 &

Question

#include<iostream.h>
#include<conio.h>
#include<string.h>

void main()
{
    clrscr();

    char str[3][10], search[10];
    int i, t = 0, k;

    cout << "Enter 3 Names Of Fruit" << endl;

    for (i = 0; i < 3; i++)
        cin >> str[i];

    cout << "Enter Fruit Name To Search" << endl;
    cin >> search;

    for (i = 0; i < 3; i++)
    {
        if (search == str[i])   // if statement is not giving true
        {
            t++;
            k = i;
        }
    }

    cout << "The " << search << " is found " << t <<
        " times and is at position " << k << endl;

    getch();
}

Answer 1

您必须使用cstring 中的std::strcmp：

完整代码：

#include<iostream>
#include<cstring>

using std::cout;
using std::endl;
using std::cin;
using std::strcmp;

int main() {

    char str[3][10], search[10];
    int i, t = 0, k;

    cout<<"Enter 3 Names Of Fruit"<<endl;

    for( i = 0; i < 3; i++ ) 
        cin>>str[i];

    cout<<"Enter Fruit Name To Search"<<endl;
    cin>>search;

    for( i = 0; i < 3; i++ ) {
        if( strcmp(search, str[i]) == 0)
        { 
            t++;
            k=i;
        }
    }

    cout << "The " << search << " is found " << t
        << " times and is at position " << k + 1 << endl;

    cin.get();
    return 0;
}

样品运行：

Enter 3 Names Of Fruit
banana mango orange
Enter Fruit Name To Search
mango
The mango is found 1 times and is at position 2