3

我有以下表格

     //all users deails
    smsusers(id,fname , lname ,primary key(id));

 //message details of users
 //one smsusers can have N messages
 user_messages(messageid,message,adddate ,sentby,visibility,
 userid,primary key(messageid),foreign key(userid) references smsusers(id),
 foreign key(sentby) references smsusers(id));


 //One message(user_message) can have N comments
 comments(comment_id,comment_on ,commented_by,comment_date,
 comment,foreign key(commented_by) references smsusers(id),
 primary key(comment_id));

 //one message(user_message) can have N post_images
 post_images(image_id,small_pic_path,userid,messageid,
 foreign key(userid) references smsusers(id),primary key(image_id));


//one message(user_message) can have N likes
 likes(element_id,element_type ,liked_by,
 foreign key(liked_by) references smsusers(id) ,adddate, 
 primary key(element_id));


  //one smsusers(user) can have 1 profile_pic
 profile_pic(pic_id varchar(200),small_pic_path ,userid ,
 foreign key(userid) references smsusers(id),primary key(pic_id));

我想获取 user_messages 的任何 messageid 和 userid 的以下详细信息

    1)all details from user_message, 
    2)last 05 comments related to messageid in ascending order from comments table 
      (one message can have multiple comments)which includes comment_id ,comment,
         comment_date,and details of commented_by(fname,lname,small_pic_path). 
    3)all small_pic_path from post_images(one message can have multiple images), 
    4)total likes from like table,
    5)all details (smsusers.*,profile_pic.*) of sentby( of table  user_messages)

我想获取所有这些详细信息。

我应该使用查询或函数来获取所有这些信息吗？

请建议一个查询或一个函数来获取所有数据。

我正在使用 MySQL DB 和 struts2

4

3 回答 3

0

4）来自like table的总喜欢，

SELECT count(*) AS total_likes FROM likes WHERE element_id = <messageID>;

5) sentby 的所有详细信息 (smsusers.*,profile_pic.*)

SELECT smsusers.*,profile_pic.* FROM user_messages
    JOIN smsusers 
        ON user_messages.sentby = smsusers.id
    JOIN profile_pic.userid = smsusers.id
WHERE user_messages = <messageID>

现在将它们全部加入一个查询中

SELECT (<Query_1>),(<Query_2>),[...],(<Query_N>)
于 2013-02-21T11:11:40.927 回答
0

1)all details from user_message

SELECT * FROM user_messages WHERE userid = <userID> AND messageid = <messageID>;

2)last 10 comments related to messageid in ascending order from comments table (one message can have multiple comments)which includes comment_id ,comment, comment_date,and details of commented_by(fname,lname,small_pic_path).

SELECT a.comment_id, a.comment, a.comment_date, b.fname || b.lname || c.small_pic_path "Commented by" 
FROM comments a, smusers b, profile_pic c, user_messages d
WHERE d.messageid = <messageID>
AND d.userid = b.id
AND b.id = c.userid
ORDER BY comment_date
LIMIT 0, 10;

3)all small_pic_path from post_images(one message can have multiple images),

SELECT small_pic_path
FROM post_images;

4)total likes from like table,

SELECT * FROM likes;

5)all details (smsusers.*,profile_pic.*) of sentby

You have not posted the structure of sentby
于 2013-02-12T12:07:30.833 回答
-1

你似乎已经得到了答案。让我知道那是怎么回事，如果你还需要什么。

于 2013-02-23T08:36:13.643 回答