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我有 EF 类，我为每个类制作了具有各种 DAL 功能（获取、设置、订购等）的模型（没有从 EF poco 类继承）。BL 将在控制器内部。对于单个模型实例，一切看起来都很好，但现在我需要绑定以查看数据列表。下面是我如何做到的一个例子。我是 MVC 新手，不确定这是否是最佳实践：

该模型：

public class CustomerWishlistModel
{
    static storeDataEntities db = new storeDataEntities();

    //Some properties of the model
    public int CustomerID { get; set; }

    public int ProductID { get; set; }

    public string ProductName { get; set; }

    public string BrandName { get; set; }

    public CustomerWishlistModel(){}

    //Get wishlists by customer
    public static List<CustomerWishlist> GetCustomerWishLists(int customerID)
    {
         return db.CustomerWishlists.Where(x => x.CustomerID == customerID).ToList();
    }

    //Convert wishlist to model
    public static CustomerWishlistModel GetWishListModel(CustomerWishlist thisWishList)
    {  
        CustomerWishlistModel thisWishListModel = new CustomerWishlistModel()
        {
            CustomerID = thisWishList.CustomerID,
            ProductID = thisWishList.ProductID,
            BrandName = thisWishList.Product.Supplier.BrandName,
            ProductName = thisWishList.Product.Name
       };

       return thisWishListModel;
    }
}

控制器：

[Authorize]
[HttpGet]
public ActionResult Index(string id)
{
    //Get all wishlists to current customer
    List<CustomerWishlist> thisWishList = CustomerWishlistModel.GetCustomerWishLists(int.Parse(id));

    //Get language from url
    Language thisLanguage = LanguageModel.GetLanguageByCulture(RouteData.Values["language"].ToString());

    if (Session["UserID"] != null && Session["UserID"].ToString() == id && thisWishList != null && thisLanguage != null)
    {
        List<CustomerWishlistModel> thisWishlistModel = new List<CustomerWishlistModel>();

        //Get all wishlists that their status is online and language equals to current
        foreach (CustomerWishlist item in thisWishList)
        {
            if (item.Product.Status == (int)EnumModel.ProductStatus.Online && item.Product.LanguageID == thisLanguage.ID)
            {
                thisWishlistModel.Add(CustomerWishlistModel.GetWishListModel(item));
            }
        }

        return View(thisWishlistModel);
    }
    else
    {
        return RedirectToAction("Login", "Customer");
    }
}

风景：

@model IEnumerable<Store.Models.CustomerWishlistModel>
@{
    Layout = "~/Views/Shared/_Layout.cshtml";
    ViewBag.Title = Resources.Store.WishList;    
}
@using (Html.BeginForm())
{
    <h2>@Resources.Store.WishList</h2>

    foreach (Store.Models.CustomerWishlistModel item in Model.ToList())
    {
         item.BrandName...... and other markup tags
    }
}
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1 回答 1

3

最佳实践是从控制器中删除任何业务逻辑，它们只假设处理调用适当的服务并将模型数据传递给视图。您的模型不应该有任何数据访问代码，而是最好将收集数据抽象到另一个类并返回一个干净的模型。例如，最流行的抽象 DAL 模式之一是存储库模式，它通过简单的接口（如Customer CustomerRepository.GetCustomer(int id).

您的所有业务逻辑也应该包含在服务中，这些服务将调用存储库以获取所需的数据并根据您的业务规则处理数据。该服务将返回一个干净的模型对象，您的控制器会将其传递给视图。简单干净。

于 2013-02-11T22:39:59.320 回答