1

我需要将 String 拆分为单个字符 Strings 的数组并获取拆分字符的计数。

例如，拆分“字符”将给出数组"c", "h", "a", "r", "a", "c", "t", "e", "r"。

编辑

是否可以使用内置函数计算拆分的字符串字符？

Array ( [c] => 2 [h] => 1 [a] => 2 [r] => 2 [t] => 1 [e] => 1 )
4

5 回答 5

4

[阵列$array

$array = str_split('Cat');


拆分str_split()后将如下所示：

ARRAY
{
   [0] = 'C'
   [1] = 'a'
   [2] = 't'
}



回答已编辑的问题

是的，您可以使用该功能count_chars()

$str = "CHARACTERS";

$array = array();

foreach (count_chars($str, 1) as $i => $val) {
   array[] = array($str, $i);
}

将输出以下内容：

ARRAY
{
   [0] = ARRAY("C" => 2)
   [1] = ARRAY("H" => 1)
}

ETC

于 2013-02-09T14:36:38.623 回答
3

使用 php 函数str_split，示例如下：

$array = str_split("cat");
于 2013-02-09T14:35:28.627 回答
2

利用str_split

$array = str_split("cat");

尝试count_chars：

<?php
$data = "Two Ts and one F.";

foreach (count_chars($data, 1) as $i => $val) {
   echo "There were $val instance(s) of \"" , chr($i) , "\" in the string.\n";
}
?>

上面的示例将输出：

There were 4 instance(s) of " " in the string.
There were 1 instance(s) of "." in the string.
There were 1 instance(s) of "F" in the string.
There were 2 instance(s) of "T" in the string.
There were 1 instance(s) of "a" in the string.
There were 1 instance(s) of "d" in the string.
There were 1 instance(s) of "e" in the string.
There were 2 instance(s) of "n" in the string.
There were 2 instance(s) of "o" in the string.
There were 1 instance(s) of "s" in the string.
There were 1 instance(s) of "w" in the string.
于 2013-02-09T14:36:15.413 回答
1

您需要使用str_split

IE

$array = str_split($str, 1);
于 2013-02-09T14:36:14.460 回答
-1

在此处使用爆炸文档 

 /* A string that doesn't contain the delimiter will simply return a one-length array of the original string. */
 $input1 = "hello";
 $input2 = "hello,there";
 var_dump( explode( ',', $input1 ) );
 var_dump( explode( ',', $input2 ) );
于 2013-02-09T14:36:55.580 回答