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我对 SQL Server 还很陌生……但我有一个问题。我编写了以下查询，它可以很好地显示 2012 年患者的所有访问（遭遇）和实验室结果。 

SELECT pat.patient_id, pat.last_name, Pat.first_name, pat.ethnic_group,
pat.race, pl.icdcode, enc.encounter_date, lab.test_performed, lab.result_value,
lab.result_units
FROM dbo.dem_patient pat
RIGHT JOIN dbo.med_problemlist as pl
ON pat.patient_id = pl.patient_id
JOIN dbo.enc_encounter as enc
ON pat.patient_id = enc.patient_id
JOIN dbo.med_labresult as lab
ON pat.patient_id = lab.patient_id
WHERE pl.icdcode like '401.9%' AND
enc.encounter_date >= '01/01/2012' AND enc.encounter_date <= '12/31/2012' AND
pat.last_name != 'test' AND (lab.test_performed = 'HgbA1c' OR 
lab.test_performed = 'Hemoglobin A1c')
GROUP BY pat.patient_id, pat.last_name, Pat.first_name, pat.ethnic_group,
pat.race, pl.icdcode, enc.encounter_date, lab.test_performed, lab.result_value,
lab.result_units
ORDER BY race, ethnic_group

上述查询的结果如下所示：

patient_id  last_name  first_name  ethnic_group  race  icdcode  encounter_date lab_result
0           smith      john        HIS           WHI   401.90   01/01/2012     9.1
0           smith      john        HIS           WHI   401.90   10/12/2012     9.2
0           smith      john        HIS           WHI   401.90   11/15/2012     9.7
5           doe        jane        NSP           BLK   401.90   01/20/2012     11
6           davids     david       NSP           BLK   401.90   04/25/2012     5.9
6           davids     david       NSP           BLK   401.90   05/04/2012     6.4

但是，我现在只需要返回那些在 2012 年 1 月 1 日至 2012 年 12 月 31 日期间访问（遭遇）超过一次的患者。它看起来像这样（从上面的结果）

patient_id  last_name  first_name  ethnic_group  race  icdcode  encounter_date lab_result
0           smith      john        HIS           WHI   401.90   01/01/2012     9.1
6           davids     david       NSP           BLK   401.90   04/25/2012     5.9

谁能帮我这个？

更新：因此，使用下面的建议，我已将 HAVING COUNT(*) > 1 添加到查询中。但是，这给了我一些我不太明白的结果。

没有 HAVING COUNT(*) > 1 语句的查询结果：

1001131     BLA 401.9   48:48.3 Hemoglobin A1c  9.9
1001131     BLA 401.9   00:00.0 Hemoglobin A1c  9.9
1001131     BLA 401.9   44:44.3 Hemoglobin A1c  9.9
1001648     BLA 401.9   50:15.6 Hemoglobin A1c  6.5
1001648     BLA 401.9   16:15.1 Hemoglobin A1c  6.5
1001648     BLA 401.9   28:04.5 Hemoglobin A1c  6.5
1001648     BLA 401.9   17:00.2 Hemoglobin A1c  6.5
1002648     BLA 401.9   17:47.8 Hemoglobin A1c  6.1
1002648     BLA 401.9   52:38.0 Hemoglobin A1c  6.1
1002648     BLA 401.9   43:47.3 Hemoglobin A1c  6.1
1002648     BLA 401.9   02:55.9 Hemoglobin A1c  6.1
1002715     BLA 401.9   37:52.4 Hemoglobin A1c  13.1
1002715     BLA 401.9   44:41.0 Hemoglobin A1c  12.6
1002715     BLA 401.9   44:41.0 Hemoglobin A1c  13.1
1002715     BLA 401.9   37:52.4 Hemoglobin A1c  10.7
1002715     BLA 401.9   37:52.4 Hemoglobin A1c  12.6
1002715     BLA 401.9   00:57.9 Hemoglobin A1c  10.7
1002715     BLA 401.9   00:57.9 Hemoglobin A1c  12.6
1002715     BLA 401.9   00:57.9 Hemoglobin A1c  13.1
1002715     BLA 401.9   38:17.6 Hemoglobin A1c  10.7
1002715     BLA 401.9   38:17.6 Hemoglobin A1c  12.6
1002715     BLA 401.9   38:17.6 Hemoglobin A1c  13.1
1002715     BLA 401.9   44:41.0 Hemoglobin A1c  10.7
1002893     BLA 401.9   33:45.4 Hemoglobin A1c  5.9
1002893     BLA 401.9   22:58.5 Hemoglobin A1c  5.9
1002893     BLA 401.9   00:00.0 Hemoglobin A1c  5.9
1002893     BLA 401.9   55:11.3 Hemoglobin A1c  5.9
1003195     BLA 401.9   34:08.7 Hemoglobin A1c  6.4
1003195     BLA 401.9   50:03.6 Hemoglobin A1c  6.4
1003195     BLA 401.9   08:36.8 Hemoglobin A1c  6.4
1003195     BLA 401.9   33:56.6 Hemoglobin A1c  6.4
1003195     BLA 401.9   34:04.3 Hemoglobin A1c  6.4

使用 HAVING 语句查询的结果：

1001937     BLA 401.9   11/14/12Hemoglobin A1c  6.3
1001937     BLA 401.9   8/14/12 Hemoglobin A1c  6.3
1001937     BLA 401.9   5/14/12 Hemoglobin A1c  6.3
1001937     BLA 401.9   2/14/12 Hemoglobin A1c  6.3
1001937     BLA 401.9   11/14/12Hemoglobin A1c  6.3
1002034     BLA 401.9   1/10/12 HEMOGLOBIN A1c  7.7
1002034     BLA 401.9   6/8/12  HEMOGLOBIN A1c  7.7
1002034     BLA 401.9   9/7/12  HEMOGLOBIN A1c  7.7
1002034     BLA 401.9   10/15/12HEMOGLOBIN A1c  7.7
1002648     BLA 401.9   2/22/12 Hemoglobin A1c  6.1
1002648     BLA 401.9   7/2/12  Hemoglobin A1c  6.1
1002648     BLA 401.9   10/2/12 Hemoglobin A1c  6.1
1002648     BLA 401.9   2/22/12 Hemoglobin A1c  6.1
1020923     BLA 401.9   1/30/12 HEMOGLOBIN A1c  10
1020923     BLA 401.9   1/30/12 Hemoglobin A1c  11.8
1020923     BLA 401.9   4/17/12 Hemoglobin A1c  11.8
1020923     BLA 401.9   5/16/12 HEMOGLOBIN A1c  10
1020923     BLA 401.9   5/16/12 Hemoglobin A1c  11.8
1020923     BLA 401.9   9/13/12 HEMOGLOBIN A1c  10
1020923     BLA 401.9   9/13/12 Hemoglobin A1c  9.3
1020923     BLA 401.9   10/1/12 HEMOGLOBIN A1c  10
1020923     BLA 401.9   10/1/12 Hemoglobin A1c  11.8
4

5 回答 5

1

从选择字段中删除日期，然后使用

Select FIELDS where condition group by FIELDS  having count(*) > 1
于 2013-02-05T17:21:09.830 回答
0

您的查询可能如下所示：

SELECT pat.patient_id, pat.last_name, Pat.first_name, pat.ethnic_group,
       pat.race, pl.icdcode, enc.encounter_date, lab.test_performed, lab.result_value,
       lab.result_units
FROM dbo.dem_patient pat
     RIGHT JOIN dbo.med_problemlist as pl
      ON pat.patient_id = pl.patient_id
     JOIN dbo.enc_encounter as enc
      ON pat.patient_id = enc.patient_id
     JOIN dbo.med_labresult as lab
      ON pat.patient_id = lab.patient_id
WHERE pl.icdcode like '401.9%' AND
       enc.encounter_date >= '01/01/2012' AND enc.encounter_date <= '12/31/2012' AND
       pat.last_name != 'test' AND (lab.test_performed = 'HgbA1c' OR 
       lab.test_performed = 'Hemoglobin A1c')
GROUP BY pat.patient_id, pat.last_name, Pat.first_name, pat.ethnic_group,
         pat.race, pl.icdcode, enc.encounter_date, lab.test_performed,lab.result_value,
          lab.result_units
HAVING COUNT(*)>1
于 2013-02-05T17:25:45.283 回答
0

在我的脑海中，将另一个连接条件添加到内联视图中，您可以从遇到次数大于 1 的集合中获取最小遭遇日期。连接条件将是 enc.encounterdate = inlineview.encounterdate。

您发布的示例结果看起来像是在寻找第一次遇到，所以使用 min，如果您想要最后一次遇到，则使用 max。

于 2013-02-05T17:27:31.877 回答
0

在您的结果中 lab_result 和 meet_date 有不同的值。请求返回用于分组数据的最小值

SELECT pat.patient_id, pat.last_name, Pat.first_name, pat.ethnic_group,
       pat.race, pl.icdcode, MIN(enc.encounter_date), MIN(lab.result_value)
FROM dbo.dem_patient pat RIGHT JOIN dbo.med_problemlist as pl ON pat.patient_id = pl.patient_id
                               JOIN dbo.enc_encounter as enc ON pat.patient_id = enc.patient_id
                               JOIN dbo.med_labresult as lab ON pat.patient_id = lab.patient_id
WHERE pl.icdcode like '401.9%' AND enc.encounter_date >= '01/01/2012' AND enc.encounter_date <= '12/31/2012' AND
      pat.last_name != 'test' AND (lab.test_performed = 'HgbA1c' OR lab.test_performed = 'Hemoglobin A1c')
GROUP BY pat.patient_id, pat.last_name, Pat.first_name, pat.ethnic_group,
         pat.race, pl.icdcode
HAVING COUNT(*) > 1
ORDER BY race, ethnic_group
于 2013-02-05T21:45:37.057 回答
0 
;WITH PatientData (patient_id,last_name, first_name, ethnic_group,
race, icdcode, encounter_date, test_performed, result_value,
result_units )
AS
(
SELECT pat.patient_id, pat.last_name, Pat.first_name, pat.ethnic_group,
pat.race, pl.icdcode, enc.encounter_date, lab.test_performed, lab.result_value,
lab.result_units
FROM dbo.dem_patient pat
RIGHT JOIN dbo.med_problemlist as pl
ON pat.patient_id = pl.patient_id
JOIN dbo.enc_encounter as enc
ON pat.patient_id = enc.patient_id
JOIN dbo.med_labresult as lab
ON pat.patient_id = lab.patient_id
WHERE pl.icdcode like '401.9%' AND
enc.encounter_date >= '01/01/2012' AND enc.encounter_date <= '12/31/2012' AND
pat.last_name != 'test' AND (lab.test_performed = 'HgbA1c' OR 
lab.test_performed = 'Hemoglobin A1c')
GROUP BY pat.patient_id, pat.last_name, Pat.first_name, pat.ethnic_group,
pat.race, pl.icdcode, enc.encounter_date, lab.test_performed, lab.result_value,
lab.result_units
)

SELECT patient_id,last_name, first_name, ethnic_group,
race, icdcode, encounter_date, test_performed, result_value,
result_units
FROM PatientData pd1 
WHERE EXISTS (SELECT patient_id 
                FROM PatientData pd2 
                WHERE p2.patient_id  = pd1.patient_id  
                GROUP BY patient_id 
                HAVING COUNT(*)>1 )
ORDER BY pd1.race, pd1.ethnic_group

这样做是创建一个名为公共表表达式 (CTE) 的临时命名结果集。这里面有所有的数据。然后选择只挑选出 CTE 中多次出现患者 ID 的那些记录。

于 2013-02-05T21:47:16.670 回答