我有表格上传图片..我想要的是通过ajax处理表格并在成功后显示jquery thinbox ..
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1 回答
2
进行ajax调用,并定义一个回调函数。
在回调函数中调用此方法:
function tb_show(caption, url, imageGroup)
这通常应该显示复选框
进行 ajax 调用:
$.ajax({
url: "yoururl.php",
cache: false,
success: function(){ // --> this defines what function needs to be called when the ajaxcall was successful.
// note that you'll need to fill the variables caption, url and imagegroup here. I don't know what they should be in your case.
function tb_show(caption, url, imageGroup);
}
});
于 2009-09-24T11:34:41.273 回答