android - 检索联系信息时遇到问题

Question

我想从我尝试通过查询检索的号码中获取联系人姓名但我没有得到结果..它正在返回号码本身......我已经将该号码保存到联系人中。

我试过的代码是......

public class MainActivity extends Activity {

@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_main);

    String x = getContactNameFromNumber("+918281306132");
    System.out.println(x);
}
private String getContactNameFromNumber(String number) {
    // define the columns I want the query to return

    System.out.println("Entering into getContactNameFromNumber");
    String[] projection = new String[] {
            Contacts.Phones.DISPLAY_NAME,
            Contacts.Phones.NUMBER };

    // encode the phone number and build the filter URI
    Uri contactUri = Uri.withAppendedPath(Contacts.Phones.CONTENT_FILTER_URL, Uri.encode(number));

    // query time
    Cursor c = getContentResolver().query(contactUri, projection, null,
            null, null);

    // if the query returns 1 or more results
    // return the first result
    if (c.moveToFirst()) {
        String name = c.getString(c
                .getColumnIndex(Contacts.Phones.DISPLAY_NAME));
        return name;
    }

    // return the original number if no match was found
    return number;
}

}

我还添加了读取手机状态权限。请有人帮我找回联系人姓名。

Answer 1

在您的代码中进行以下更改

Uri contactUri = Uri.withAppendedPath(Phone.CONTENT_URI, Uri.encode(number));

和

if (c.moveToFirst()) {
    String name = c.getString(c
            .getColumnIndex(ContactsContract.CommonDataKinds.Phone.DISPLAY_NAME));
    return name;
}

试试看，希望对你有帮助。:)

Answer 2

ContentResolver cr = getContentResolver();
        Cursor cur = cr.query(ContactsContract.Contacts.CONTENT_URI, null,
                null, null, null);
        if (cur.getCount() > 0) {
            while (cur.moveToNext()) {
                String id = cur.getString(cur
                        .getColumnIndex(ContactsContract.Contacts._ID));
                String name = cur
                        .getString(cur
                                .getColumnIndex(ContactsContract.Contacts.DISPLAY_NAME));

                System.out.println(name + "name");

                if (Integer
                        .parseInt(cur.getString(cur
                                .getColumnIndex(ContactsContract.Contacts.HAS_PHONE_NUMBER))) > 0) {
                    // Query phone here. Covered next

                }
            }

这段代码为我工作

Answer 3

你可以试试我的片段：

public static String findContactByNumber(String phoneNumber,
        ContentResolver cr) {

    Uri lookupUri = Uri.withAppendedPath(PhoneLookup.CONTENT_FILTER_URI,
            Uri.encode(phoneNumber));

    String[] phoneNoProjections = { PhoneLookup._ID,
            PhoneLookup.DISPLAY_NAME };

    Cursor cursor = cr.query(lookupUri, phoneNoProjections, null, null,
            null);

    try {

        if (cursor.moveToFirst()) {

            return cursor.getString(1); //1 is the display name index. 0 is id.

        }

    } finally {

        if (cursor != null)

            cursor.close();

    }

    return null;

}