iphone - NSMutableDictionary 上的 EXC_BAD_ACCESS

Question

我从 iOS 开发开始，我有这个代码：

首先我声明 listOfItems NSMutableArray：

@interface SAMasterViewController () {
    NSMutableArray *listOfItems;
}
@end

现在，这是给我“EXC_BAD_ACCESS（代码=1，地址=0x5fc260000）”错误的代码部分。错误在“individual_data”对象的最后一行给出。

listOfItems = [[NSMutableArray alloc] init];
for(NSDictionary *tweetDict in statuses) {
    NSString  *text          = [tweetDict objectForKey:@"text"];
    NSString  *screenName    = [[tweetDict objectForKey:@"user"] objectForKey:@"screen_name"];
    NSString  *img_url       = [[tweetDict objectForKey:@"user"] objectForKey:@"profile_image_url"];
    NSInteger unique_id      = [[tweetDict objectForKey:@"id"] intValue];
    NSInteger user_id        = [[[tweetDict objectForKey:@"user"] objectForKey:@"id"] intValue ];

    NSMutableDictionary *individual_data = [NSMutableDictionary dictionaryWithObjectsAndKeys:
                                            text, @"text_tweet",
                                            screenName,@"user_name",
                                            img_url, @"img_url",
                                            unique_id, @"unique_id",
                                            user_id, @"user_id", nil];
    [listOfItems addObject:individual_data];
}

提前致谢。

Answer 1

您不能将NSIntegers 或任何其他非 Objective-C 类放入数组或字典中。您需要将它们包装在一个NSNumber.

NSMutableDictionary *individual_data = [NSMutableDictionary dictionaryWithObjectsAndKeys:
                                            text, @"text_tweet",
                                            screenName,@"user_name",
                                            img_url, @"img_url",
                                            [NSNumber numberWithInteger:unique_id], @"unique_id",
                                            [NSNumber numberWithInteger:user_id], @"user_id", nil];
//Or if you want to use literals
NSMutableDictionary *individual_data = [NSMutableDictionary dictionaryWithObjectsAndKeys:
                                            text, @"text_tweet",
                                            screenName,@"user_name",
                                            img_url, @"img_url",
                                            @(unique_id), @"unique_id",
                                            @(user_id), @"user_id", nil];