我正在学习创建自己的数据库，到目前为止，我已经“感谢教程和 stackoverflow”来创建注册页面。
注册后，他们输入用户名和密码，然后打开上传页面。
上传房屋详情
在上传页面上，他们输入城市： 价格： 说明： 卧室： 浴室： 照片：
到目前为止，一旦他们输入了它在索引页面上显示的数据，我就完成了分页，重新调整了上传图像的大小，一切正常。
我的下一步是在索引页面上为每个条目打开一个显示其数据的新窗口。
问题是我很难找到代码，我希望用户在上传房屋详细信息时为其详细信息页面输入名称。
并且它不以 .php 或 .html 结尾，只需 www.mysite.com/the-desired-name
到目前为止，我的代码可能使用了糟糕的代码，但它工作正常，它帮助我实现了我想要的，直到我有经验来完善它。
我的代码是上传页面
<form enctype="multipart/form-data" action="add.php" method="POST">
City: <input type="text" name="city"><br>
Price: <input type="text" name = "price"><br>
Decription: <input type="text" name ="description"><br>
Bedrooms: <input type="text" name="bed"><br>
Bathrooms: <input type="text" name="bath"><br>
Your desired link name MYSITE.COM/ <input type="text" name="link"><br>
Photo: <input type="file" name="photo"><br>
<input type="submit" value="Add">
</form>
然后它通过上传
<?php
//This is the directory where images will be saved
$target = "upload/";
$target = $target . basename( $_FILES['photo']['name']);
//This gets all the other information from the form
$city=$_POST['city'];
$price=$_POST['price'];
$description=$_POST['description'];
$bed=$_POST['bed'];
$bath=$_POST['bath'];
$link=$_POST['link'];
$pic=($_FILES['photo']['name']);
// Connects to your Database
mysql_connect("host", "username", "password") or die(mysql_error()) ;
mysql_select_db("mydatabase") or die(mysql_error()) ;
//Writes the information to the database
mysql_query("INSERT INTO `employees` VALUES ('$city', '$price', '$description', '$bed', '$bath', '$link', '$pic')") ;
if(move_uploaded_file($_FILES['photo']['tmp_name'], $target))
{
require_once 'SimpleImage.php';
$image = new SimpleImage();
$image->load($target);
$image->resize(50,50);
$image->save($target);
//Tells you if its all ok
echo "<script>window.location = 'http://www.mysite.com'</script>";
}
else {
//Gives and error if its not
echo "Sorry, there was a problem uploading your file.";
}
?>
然后它显示在索引页面上
<?php
// Connects to your Database
mysql_connect("host", "username", "password") or die(mysql_error()) ;
mysql_select_db("mydatabase") or die(mysql_error()) ;
if (isset($_GET["page"])) { $page = $_GET["page"]; } else { $page=1; };
$start_from = ($page-1) * 2;
$data = mysql_query("SELECT * FROM employees ORDER BY bath ASC LIMIT $start_from, 2") or die(mysql_error());
//Puts it into an array
while($info = mysql_fetch_array( $data ))
{
?>
<?php
//Outputs the image and other data
echo "<img src=http://www.mysite.com/upload/".$info['photo'] . " /><br />";
echo "<b>City:</b> ".$info['city'] . " ";
echo "<b>Price:</b> ".$info['price'] . " ";
echo "<b>Bed:</b> ".$info['bed'] . " ";
echo "<b>Bath:</b> ".$info['bath'] . " ";
echo "<b>Extra:</b> ".$info['description'] . " ";
echo "<b>Link:</b> <u>www.mysite.com/</u> ".$info['link'] . " <br /><br /></a>";
}?>
<?php
$data = mysql_query("SELECT COUNT(photo) FROM employees") or die(mysql_error());
$info = mysql_fetch_row($data);
$total_records = $info[0];
$total_pages = ceil($total_records / 2);
for ($i=1; $i<=$total_pages; $i++) {
echo "<a href='index.php?page=".$i."'>".$i."</a> ";
};
?>