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使用 MS Word 2010 我希望 Mailmerge 使用宏运行,将每条记录保存为单独的文件,以 PDF 格式使用其中一个字段作为文件名。这将为我节省大量时间。

我遇到的问题是格式完全丢失了,就好像它只是复制文本并将其粘贴到新文档中一样。有什么办法可以保护格式,因为没有它它是徒劳的......

提前致谢。

Sub splitter()

Dim i As Integer
Dim Source As Document
Dim Target As Document
Dim Letter As Range
Dim oField As Field
Dim FileNum As String

Set Source = ActiveDocument

ActiveDocument.MailMerge.DataSource.ActiveRecord = wdLastRecord

For i = 1 To ActiveDocument.MailMerge.DataSource.ActiveRecord
    ActiveDocument.MailMerge.DataSource.ActiveRecord = i
    Set Letter = Source.Range
        For Each oField In Letter.Fields
        If oField.Type = wdFieldMergeField Then
            If InStr(oField.Code.Text, "INV_ID") > 0 Then
            FileNum = oField.Result
            End If
        End If
        Next oField
    Set Target = Documents.Add
    Target.Range = Letter
    Target.SaveAs2 "C:\BACS\INVOICING\INVOICES\Word Export\" & FileNum, 17
    Target.Close
    Next i
End Sub
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2 回答 2

0

如何使用保存?

此示例代码循环遍历邮件合并文档中的每个邮件合并项目,将项目作为字母打开,并使用 DataSource 中的字段作为文件名将其保存为 PDF。没有错误编码,也没有尝试检查重复的文件名。这是一个片段。

Dim iRec As Integer
Dim docMail As Document
Dim docLetters As Document


Set docMail = ActiveDocument

''There is a problem with the recordcount property returning -1
''http://msdn.microsoft.com/en-us/library/office/ff838901.aspx
docMail.MailMerge.DataSource.ActiveRecord = wdLastRecord
iRec = docMail.MailMerge.DataSource.ActiveRecord

docMail.MailMerge.DataSource.ActiveRecord = wdFirstRecord

For i = 1 To iRec
    With docMail.MailMerge
        .Destination = wdSendToNewDocument
        .SuppressBlankLines = True
        With .DataSource
            .FirstRecord = i
            .LastRecord = i
            '' This will be the file name
            '' the test data source had unique surnames
            '' in a field (column) called Surname
            sFName = .DataFields("Surname").Value
        End With
        .Execute Pause:=False
        Set docLetters = ActiveDocument
    End With
    docLetters.ExportAsFixedFormat OutputFileName:= _
        "Z:\docs\" & sFName & ".pdf", ExportFormat:= _
        wdExportFormatPDF, OpenAfterExport:=False, OptimizeFor:= _
        wdExportOptimizeForPrint, Range:=wdExportAllDocument, From:=1, To:=1, _
        Item:=wdExportDocumentContent, IncludeDocProps:=True, KeepIRM:=True, _
        CreateBookmarks:=wdExportCreateNoBookmarks, DocStructureTags:=True, _
        BitmapMissingFonts:=True, UseISO19005_1:=False
    docLetters.Close False

    docMail.MailMerge.DataSource.ActiveRecord = wdNextRecord
Next
于 2013-02-01T10:57:04.073 回答
0

首先让我在应得的地方给予赞扬,因为我对编写宏一无所知。事实上,这是我第一次尝试使用宏,更不用说修改代码了。只有 24 岁的 Basic 知识(是原始知识,不是 Visual Basic)和 Fortran(不是穿孔卡 Fortan,但非常接近)我从http://raduner.ch/blog/microsoft-获取了 Mr.Raduner 宏word-mail-merge-into-single-documents, Remou 用于生成上述 pdf 的宏代码,以及其他一些,并结合了不同方面和 PRESTO !!!我显然很幸运,但它适用于 MS Word 2010。希望它也适用于其他所有人。我正在加载单个 pdf 创建者和单个 word 文件创建者。我希望了解 Visual Basic 的人能将其清理干净,并使其对其他人更加用户友好。

单个字文件宏(请注意,您的 Excel 数据源中必须有一个“文件名”列):

Sub SaveIndividualWordFiles()
Dim iRec As Integer
Dim docMail As Document
Dim docLetters As Document
Dim savePath As String

Set docMail = ActiveDocument
''There is a problem with the recordcount property returning -1
''http://msdn.microsoft.com/en-us/library/office/ff838901.aspx

savePath = ActiveDocument.Path & "\"

docMail.MailMerge.DataSource.ActiveRecord = wdLastRecord
iRec = docMail.MailMerge.DataSource.ActiveRecord
docMail.MailMerge.DataSource.ActiveRecord = wdFirstRecord

For i = 1 To iRec
 With docMail.MailMerge
    .Destination = wdSendToNewDocument
    .SuppressBlankLines = True
    With .DataSource
        .FirstRecord = i
        .LastRecord = i
        '' This will be the file name
        '' the test data source had unique surnames
        '' in a field (column) called FileName
        sFName = .DataFields("FileName").Value
    End With
    .Execute Pause:=False
    Set docLetters = ActiveDocument
  End With

' Save generated document and close it after saving
        docLetters.SaveAs FileName:=savePath & sFName
        docLetters.Close False

  docMail.MailMerge.DataSource.ActiveRecord = wdNextRecord
Next
End Sub
于 2013-12-06T12:16:47.117 回答