我有一个需要使用HABTM的数据模型，如下：
surveys
(
id int(11) NOT NULL AUTO_INCREMENT,
user_id int(11) NOT NULL,
title varchar(50) DEFAULT NULL,
created timestamp NOT NULL DEFAULT CURRENT_TIMESTAMP,
modified timestamp NOT NULL DEFAULT '0000-00-00 00:00:00',
PRIMARY KEY (id),
KEY user_id (user_id)
);
questions
(
id int(11) NOT NULL AUTO_INCREMENT,
user_id int(11) NOT NULL,
title varchar(50) NOT NULL,
body text NOT NULL,
created timestamp NOT NULL DEFAULT CURRENT_TIMESTAMP,
modified timestamp NOT NULL DEFAULT '0000-00-00 00:00:00',
PRIMARY KEY (id),
KEY user_id (user_id)
);
questions_surveys
(
id int(11) NOT NULL AUTO_INCREMENT,
survey_id int(11) NOT NULL,
question_id int(11) NOT NULL,
created timestamp NOT NULL DEFAULT CURRENT_TIMESTAMP,
modified timestamp NOT NULL DEFAULT '0000-00-00 00:00:00',
PRIMARY KEY (id),
KEY survey_id (survey_id),
KEY question_id (question_id)
);
以及相关的外键：
ALTER TABLE questions_surveys
ADD CONSTRAINT questions_surveys_ibfk_1 FOREIGN KEY(survey_id) REFERENCES surveys(id);
ALTER TABLE questions_surveys
ADD CONSTRAINT questions_surveys_ibfk_2 FOREIGN KEY(question_id) REFERENCES questions(id);
问题和调查具有 HABTM 关系，因此一项调查有许多问题，而一个问题可以在许多不同的调查中。
在 Survey.php 中：
public $hasAndBelongsToMany = array(
'Question' => array(
'className' => 'Question',
'joinTable' => 'questions_surveys',
'foreignKey' => 'survey_id',
'associationForeignKey' => 'question_id'
)
);
在 Question.php 中：
public $hasAndBelongsToMany = array(
'Survey' => array(
'className' => 'Survey',
'joinTable' => 'questions_surveys',
'foreignKey' => 'question_id',
'associationForeignKey' => 'survey_id'
)
);
这是我在 SurveysController.php 中添加的控制器：
public function add()
{
$this->set('fields', $this->Survey->getFields());
$this->set('users', $this->Survey->User->find('list', array('fields' => array('id', 'username'))));
$this->set('questions', $this->Question->find('list', array('fields' => array('id', 'body'))));
if (!empty($this->data))
{
$this->Survey->saveAll($this->data['Survey']);
foreach($this->data['Question']['id'] as $question_id)
{
$newdata[] = array('Survey' => array('id' => $this->Survey->getInsertID()), 'Question' => array('id' => $question_id));
}
if ($this->Survey->saveAll($newdata))
{
$this->Session->setFlash('The survey was successfully added!');
$this->redirect(array('action'=>'index'));
}
else
{
$this->Session->setFlash('Unable to add survey.');
}
}
}
首先保存新调查，然后将每个 question_survey 添加到一个数组中，然后一次添加所有这些。数据如下所示：
Array
(
[0] => Array
(
[Survey] => Array
(
[id] => 17
)
[Question] => Array
(
[id] => 1
)
)
[1] => Array
(
[Survey] => Array
(
[id] => 17
)
[Question] => Array
(
[id] => 2
)
)
[2] => Array
(
[Survey] => Array
(
[id] => 17
)
[Question] => Array
(
[id] => 3
)
)
[3] => Array
(
[Survey] => Array
(
[id] => 17
)
[Question] => Array
(
[id] => 4
)
)
[4] => Array
(
[Survey] => Array
(
[id] => 17
)
[Question] => Array
(
[id] => 5
)
)
[5] => Array
(
[Survey] => Array
(
[id] => 17
)
[Question] => Array
(
[id] => 6
)
)
[6] => Array
(
[Survey] => Array
(
[id] => 17
)
[Question] => Array
(
[id] => 7
)
)
[7] => Array
(
[Survey] => Array
(
[id] => 17
)
[Question] => Array
(
[id] => 8
)
)
[8] => Array
(
[Survey] => Array
(
[id] => 17
)
[Question] => Array
(
[id] => 9
)
)
[9] => Array
(
[Survey] => Array
(
[id] => 17
)
[Question] => Array
(
[id] => 10
)
)
)
我不断收到此错误：
错误：SQLSTATE [42S22]：找不到列：1054 'where 子句'
SQL 查询中的未知列'QuestionsSurvey.survey_id'：SELECTAppModel。question_id从engage。在questions_surveys哪里。= 13AppModelQuestionsSurveysurvey_id
据我所知，一切都是按照 CakePHP 标准命名的，我尝试使用 'with' => 'QuestionsSurvey'，但得到这个错误：
缺少数据库表错误：在数据源默认值中找不到模型 QuestionsSurvey 的表 app_models。
和 'with' => 'QuestionsSurveys'，但得到同样的错误：
缺少数据库表错误：在数据源默认值中找不到模型 QuestionsSurveys 的表 app_models。
我已经尝试将模型三重奏转换为 hasMany through 模型（没有用，只是说回到 HABTM）。
我已经为数据使用了各种不同的格式（CakePHP Saving Your Data），但也没有运气。
我难住了。有人知道我做错了什么吗？另外，我为非常长的条目和代码部分道歉，但我想确保是彻底的。
感谢您的时间！
马特