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我有3 张桌子： 

    Manager: manager_id, taluka_name  
    Employee: employee_id, employee_manager_id   
    Target: target_id, target_employee_id

现在我必须明智地显示所有目标taluka_name的 ListView 。我正在使用 greenDao 与 SQlite 数据库进行交互。

这是我尝试过的过程，使用我使用的方法花费的时间太长： 

    Step1: Get Manager ID for the taluka name from the DB.
    Step2: Get Employee for the Target table->Employee ID.
    Step3: Get Manager ID from the Employee table.
    Step4: Compare if Both Manager ID are equal {if YES then target 
           belongs to that taluka}

以下是我想使用 Greendao 完成的查询类型 

        SELECT *
        FROM target t, location l, current c
        WHERE t.target_location_id = l.location_id
        AND t.target_location_id = c.school_id
        AND t.target_status <> '0'
        AND t.target_status <> '4'
        AND DATEDIFF(NOW(),t.target_exec_end_time)<7
4

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