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我在网上找到了这个片段，它使用整数在 java 中创建了一个类似 array_intersect 的函数。

样本：

        int[] intersect(int[] arr1, int[] arr2) {
            int count = 0;
            for(int a = 0; a < arr1.length; a++) {
                for(int b = 0; b < arr2.length; b++) {
                    if(arr1[a] == arr2[b]) {
                        count++;
                        break;
                    }
                }
            }

            int[] result = new int[count];
            count = 0;
            for(int a = 0; a < arr1.length; a++) {
                for(int b = 0; b < arr2.length; b++) {
                    if(arr1[a] == arr2[b]) {
                        result[count++] = arr1[a];
                        break;
                    }
                }
            }

            return result;
        }

        int[] arr1 = new int[] {10, 20, 30, 40, 50, 60, 70, 80, 90, 100,
         95, 85, 75, 65, 55, 45, 35, 25, 15, 05,
         10, 15, 20, 25, 30, 35, 40, 45, 50, 55};

        int[] arr2 = new int[] {15, 25, 35, 45, 55,
         12, 22, 32, 43, 52,
         15, 25, 35, 45, 55};

        int[] p1 = this.unique(arr1);
        int[] p2 = this.unique(arr2);
        int[] intersectResults = this.intersect(arr1, arr2);

            for(int a = 0; a < intersectResults.length; a++) {
                System.out.print(intersectResults[a] + "    ");
            }

但是当我将其更改为：

        String[] intersect(String[] a_yourname, String[] a_crushname) {
            int count = 0;
            for(int a = 0; a < a_yourname.length; a++) {
                for(int b = 0; b < a_crushname.length; b++) {
                    if(a_yourname[a] == a_crushname[b]) {
                        count++;
                        break;
                    }
                }
            }

            String[] result = new String[count];
            count = 0;
            for(int a = 0; a < a_yourname.length; a++) {
                for(int b = 0; b < a_crushname.length; b++) {
                    if(a_yourname[a] == a_crushname[b]) {
                        result[count++] = a_yourname[a];
                        break;
                    }
                }
            }

            return result;
        }

     String[] flames = this.intersect(a_yourname, a_crushname);
            //String[] p23 = this.unique(arr2);
             System.out.println("heheh" +flames.length);
             for(int a = 0; a < flames.length; a++) {
                System.out.print(flames[a] + "    ");
            }

有人可以向我解释我在这里做错了什么吗？我真的不熟悉Java。

a_yourname并且a_crushname都是字符串数组。

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1 回答 1

1

代码：

    String[] a = new String[] { "aa", "bb", "cc" };
    String[] b = new String[] { "bb", "cc", "dd" };

    Set<String> setA = new HashSet<String>(Arrays.asList(a));
    List<String> listB = Arrays.asList(b);
    setA.retainAll(listB);
    System.out.println(setA);

你可以在这里看到结果：http: //ideone.com/tKg5xa

如果您真的希望将结果作为数组：

String[] out = setA.toArray(new String[setA.size()]);

同样，如果您只想遍历结果，则无需使用数组。谷歌“Java for each”或拿起一本 Java 书。

于 2013-01-26T11:32:59.760 回答