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我制作了一个井字游戏,并且正在制作另一个代码更少的版本。无论如何...这是我的代码...我在 do while 语句之间使用了一些代码,但是是的...

    var rc = new Random();
    do
    {
        storeRI = rc.Next(1, 9);

        if (storeRI == 1 & button1.Text == "")
        {
            button1.Text = "O";
            Turn = 1;
            TestWin();
            break;
        }
        else if (storeRI == 2 & button2.Text == "")
        {
            button2.Text = "O";
            Turn = 1;
            TestWin();
            break;
        }


    } while (Turn == 2 & button1.Text == "" | button2.Text == "" | button3.Text == "" | button3.Text == "" | button4.Text == "" | button5.Text == "" | button6.Text == "" | button7.Text == "" | button8.Text == "" | button9.Text == "");
}
else
{
    MessageBox.Show("It's a draw");
}

我主要想专注于这段代码......缩短...... :)

 } while (Turn == 2 & button1.Text == "" | button2.Text == "" | button3.Text == "" | button3.Text == "" | button4.Text == "" | button5.Text == "" | button6.Text == "" | button7.Text == "" | button8.Text == "" | button9.Text == "");
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1 回答 1

5

从您的各个按钮创建一个按钮列表,然后将其更改为

while(Turn==2 && buttons.Any(b => b.Text == ""))

通常有 9 个按钮,它们可能应该放在一个数组或列表中以便于访问:

Button[] buttons = new Button[] {button1, button2, button3, ... } ;

然后你可以访问它buttons[0]而不是button1等。

我会在您的表单初始化程序中执行此操作,而不是使用按需执行此操作的函数。

于 2013-01-26T02:18:25.393 回答